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POSilence the stdout of a function in Python without trashing sys.stdout and restoring each function call
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Id
2828953
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AcceptedAnswerId
2829036
AnswerCount
8
ClosedDate
CommentCount
3
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CreationDate
2010-05-13T17:37:52.247
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14
LastActivityDate
2018-07-17T06:34:07.360
LastEditDate
2015-05-07T22:59:40.127
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1832942
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329344
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0
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1
Score
37
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26275
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text
Body
Is there a way in Python to silence stdout without wrapping a function call like following? Original Broken Code: <pre><code>from sys import stdout from copy import copy save_stdout = copy(stdout) stdout = open('trash','w') foo() stdout = save_stdout </code></pre> Edit: Corrected code from Alex Martelli <pre><code>import sys save_stdout = sys.stdout sys.stdout = open('trash', 'w') foo() sys.stdout = save_stdout </code></pre> That way works but appears to be terribly inefficient. There has to be a better way. Any ideas?
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<python><stdout>
Title
Silence the stdout of a function in Python without trashing sys.stdout and restoring each function call
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1. PO
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1. PTQuestion
UserLastEditorUserId
1. USMichael Currie
UserOwnerUserId
1. USTim McJilton
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 POSilence the stdout of a function in Python without trashing sys.stdout and restoring each function call
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1. COI'd say you should leave it uncorrected, since Alex already did it for you. It would make more sense to who is reading.
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 POSilence the stdout of a function in Python without trashing sys.stdout and restoring each function call
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 UScregox
2. COCawas: I am going to add my initial uncorrected one back above it. Or something similar with the same errors. Good call
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 POSilence the stdout of a function in Python without trashing sys.stdout and restoring each function call
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 USTim McJilton

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