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POUsing a string inside the DocumentBuilder parse method (need it for parsing XML using XPath)
 

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  1. POUsing a string inside the DocumentBuilder parse method (need it for parsing XML using XPath)
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    <p>I'm trying to create a RESTful webservice using a Java Servlet. The problem is I have to pass via POST method to a webserver a request. The content of this request is not a parameter but the body itself.</p> <p>So I basically send from ruby something like this: </p> <pre><code>url = URI.parse(@host) req = Net::HTTP::Post.new('/WebService/WebServiceServlet') req['Content-Type'] = "text/xml" # req.basic_auth 'account', 'password' req.body = data response = Net::HTTP.start(url.host, url.port){ |http| puts http.request(req).body } </code></pre> <p>Then I have to retrieve the body of this request in my servlet. I use the classic readline, so I have a string. The problem is when I have to parse it as XML:</p> <pre><code>private void useXML( final String soft, final PrintWriter out) throws ParserConfigurationException, SAXException, IOException, XPathExpressionException, FileNotFoundException { DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); // never forget this! DocumentBuilder builder = domFactory.newDocumentBuilder(); Document doc = builder.parse(soft); XPathFactory factory = XPathFactory.newInstance(); XPath xpath = factory.newXPath(); XPathExpression expr = xpath.compile("//software/text()"); Object result = expr.evaluate(doc, XPathConstants.NODESET); NodeList nodes = (NodeList) result; for (int i = 0; i &lt; nodes.getLength(); i++) { out.println(nodes.item(i).getNodeValue()); } } </code></pre> <p></p> <p>The problem is that <code>builder.parse()</code> accepts: <code>parse(File f)</code>, <code>parse(InputSource is)</code>, <code>parse(InputStream is)</code>.</p> <p>Is there any way I can transform my xml string in an InputSource or something like that? I know it could be a dummy question but Java is not my thing, I'm forced to use it and I'm not very skilled.</p>
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    1. USDimitre Novatchev
    1. USdierre
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    1. COThank you Dimitre for the editing. I'm getting used to this format code.
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      1. USdierre
    2. COCan you post sample XML that works with this code? I am working on a similar design and my node, following the xpath query is coming back null, so I suspect my xpath expression or my xml is not well-formed.
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