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POVB.NET - Removing a number from a random number generator
 

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  1. POVB.NET - Removing a number from a random number generator
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    <p>I am trying to create a lottery simulator. The lottery has 6 numbers, the number generated must be between 1 - 49 and cannot be in the next number generated. I have tried using the OR function but I'm not entirely sure if I am using it properly. Any help would be great. Thanks.</p> <pre><code>Public Class Form1 Private Sub cmdRun_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdRun.Click ''#Creates a new Random class in VB.NET Dim RandomClass As New Random() ''#################################### Dim RandomNumber1 As Integer RandomNumber1 = RandomClass.Next(1, 49) ''#Displays first number generated txtFirst.Text = (RandomNumber1) ''#################################### Dim RandomNumber2 As Integer RandomNumber2 = RandomClass.Next(1, 49) If RandomNumber2 = RandomNumber1 Then RandomNumber2 = RandomClass.Next(1, 49) End If ''#Displays second number generated txtSecond.Text = (RandomNumber2) ''#################################### Dim RandomNumber3 As Integer RandomNumber3 = RandomClass.Next(1, 49) If RandomNumber3 = RandomNumber2 Or RandomNumber2 Then RandomNumber3 = RandomClass.Next(1, 49) End If ''#Displays third number generated txtThird.Text = (RandomNumber3) ''#################################### Dim RandomNumber4 As Integer RandomNumber4 = RandomClass.Next(1, 49) If RandomNumber4 = RandomNumber3 Or RandomNumber2 Or RandomNumber1 Then RandomNumber4 = RandomClass.Next(1, 49) End If ''#Displays fourth number generated txtFourth.Text = (RandomNumber4) ''#################################### Dim RandomNumber5 As Integer RandomNumber5 = RandomClass.Next(1, 49) If RandomNumber5 = RandomNumber4 Or RandomNumber3 Or RandomNumber2 Or RandomNumber1 Then RandomNumber5 = RandomClass.Next(1, 49) End If ''#Displays fifth number generated txtFifth.Text = (RandomNumber5) ''#################################### Dim RandomNumber6 As Integer RandomNumber6 = RandomClass.Next(1, 49) If RandomNumber6 = RandomNumber5, RandomNumber4, RandomNumber3, RandomNumber2, RandomNumber1 Then RandomNumber6 = RandomClass.Next(1, 49) End If ''#Displays sixth number generated txtSixth.Text = (RandomNumber6) End Sub </code></pre>
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    1. USJoel Coehoorn
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    1. CONote that `Next(1, 49)` doesn't return a random number in the range 1-49, but in the range 1-48.
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      1. USGuffa
 

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