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    <p><strong>EDIT</strong></p> <p>Here are two versions. One using <code>ArrayList</code> and other using <code>HashSet</code> </p> <p>Compare them and create your <strong>own</strong> version from this, until you get what you need. </p> <p>This should be enough to cover the:</p> <blockquote> <p><em>P.S: It is not a school assignment :) So if you just guide me it will be enough</em></p> </blockquote> <p>part of your question.</p> <p><strong>continuing with the original answer:</strong> </p> <p>You may use a <code>java.util.Collection</code> and/or <code>java.util.ArrayList</code> for that. </p> <p>The <a href="http://java.sun.com/javase/6/docs/api/java/util/Collection.html#retainAll%28java.util.Collection%29" rel="noreferrer">retainAll</a> method does the following:</p> <blockquote> <p><em>Retains only the elements in this collection that are contained in the specified collection</em></p> </blockquote> <p>see this sample:</p> <pre><code>import java.util.Collection; import java.util.ArrayList; import java.util.Arrays; public class Repeated { public static void main( String [] args ) { Collection listOne = new ArrayList(Arrays.asList("milan","dingo", "elpha", "hafil", "meat", "iga", "neeta.peeta")); Collection listTwo = new ArrayList(Arrays.asList("hafil", "iga", "binga", "mike", "dingo")); listOne.retainAll( listTwo ); System.out.println( listOne ); } } </code></pre> <p><strong>EDIT</strong></p> <p>For the second part ( similar values ) you may use the <a href="http://java.sun.com/javase/6/docs/api/java/util/Collection.html#removeAll%28java.util.Collection%29" rel="noreferrer">removeAll</a> method:</p> <blockquote> <p><em>Removes all of this collection's elements that are also contained in the specified collection.</em></p> </blockquote> <p>This second version gives you also the similar values and handles repeated ( by discarding them).</p> <p>This time the <code>Collection</code> could be a <code>Set</code> instead of a <code>List</code> ( the difference is, the Set doesn't allow repeated values ) </p> <pre><code>import java.util.Collection; import java.util.HashSet; import java.util.Arrays; class Repeated { public static void main( String [] args ) { Collection&lt;String&gt; listOne = Arrays.asList("milan","iga", "dingo","iga", "elpha","iga", "hafil","iga", "meat","iga", "neeta.peeta","iga"); Collection&lt;String&gt; listTwo = Arrays.asList("hafil", "iga", "binga", "mike", "dingo","dingo","dingo"); Collection&lt;String&gt; similar = new HashSet&lt;String&gt;( listOne ); Collection&lt;String&gt; different = new HashSet&lt;String&gt;(); different.addAll( listOne ); different.addAll( listTwo ); similar.retainAll( listTwo ); different.removeAll( similar ); System.out.printf("One:%s%nTwo:%s%nSimilar:%s%nDifferent:%s%n", listOne, listTwo, similar, different); } } </code></pre> <p>Output:</p> <pre><code>$ java Repeated One:[milan, iga, dingo, iga, elpha, iga, hafil, iga, meat, iga, neeta.peeta, iga] Two:[hafil, iga, binga, mike, dingo, dingo, dingo] Similar:[dingo, iga, hafil] Different:[mike, binga, milan, meat, elpha, neeta.peeta] </code></pre> <p>If it doesn't do exactly what you need, it gives you a good start so you can handle from here. </p> <p>Question for the reader: How would you include all the repeated values?</p>
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    1. CO@Oscar, My exact thought, but I was not sure if we could have modified the contents of `listOne`, but +1 anyways!
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    2. COYou shouldn't use raw types.
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    3. CO@poygenelubricants what do you mean by *raw types* not generics? Why not?
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