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POPractical Scheme Programming
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2659227
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2010-04-17T17:04:40.720
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2010-06-08T02:12:33.930
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2010-06-08T02:12:33.930
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text
Body
It's been a few months since I've touched Scheme and decided to implement a command line income partitioner using Scheme. My initial implementation used plain recursion over the continuation, but I figured a continuation would be more appropriate to this type of program. I would appreciate it if anyone (more skilled with Scheme than I) could take a look at this and suggest improvements. I'm that the multiple <code>(display...</code> lines is an ideal opportunity to use a macro as well (I just haven't gotten to macros yet). <pre><code>(define (ab-income) (call/cc (lambda (cc) (let ((out (display "Income: ")) (income (string->number (read-line)))) (cond ((<= income 600) (display (format "Please enter an amount greater than $600.00~n~n")) (cc (ab-income))) (else (let ((bills (* (/ 30 100) income)) (taxes (* (/ 20 100) income)) (savings (* (/ 10 100) income)) (checking (* (/ 40 100) income))) (display (format "~nDeduct for bills:---------------------- $~a~n" (real->decimal-string bills 2))) (display (format "Deduct for taxes:---------------------- $~a~n" (real->decimal-string taxes 2))) (display (format "Deduct for savings:-------------------- $~a~n" (real->decimal-string savings 2))) (display (format "Remainder for checking:---------------- $~a~n" (real->decimal-string checking 2)))))))))) </code></pre> Invoking <code>(ab-income)</code> asks for input and if anything below 600 is provided it (from my understanding) returns <code>(ab-income)</code> at the <code>current-continuation</code>. My first implementation (as I said earlier) used plain-jane recursion. It wasn't bad at all either but I figured every return call to <code>(ab-income)</code> if the value was below 600 kept expanding the function. (please correct me if that apprehension is incorrect!)
Tags
<scheme><racket><continuations>
Title
Practical Scheme Programming
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1. USEli Barzilay
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1. USIxmatus
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