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    <p>The test fails, because you have reached the accuracy of the binary floating point representation, which is approximately 16 digits with <a href="http://en.wikipedia.org/wiki/Double_precision" rel="nofollow noreferrer">IEEE754 double precision</a>. Multiplying by 649632196443.4279 by 10000 will truncate the binary representation, leading to errors when rounding and dividing afterwards, thereby invalidating the result of your function completely.</p> <p>For more details see <a href="http://en.wikipedia.org/wiki/Floating_point#Accuracy_problems" rel="nofollow noreferrer">http://en.wikipedia.org/wiki/Floating_point#Accuracy_problems</a></p> <p>A better way would be to check whether the <code>n+1</code> decimal places are below a certain threshold. If <code>d - round(d)</code> is less than <a href="http://en.wikipedia.org/wiki/Epsilon" rel="nofollow noreferrer"><code>epsilon</code></a> (see <a href="http://en.wikipedia.org/wiki/Limit_(mathematics)" rel="nofollow noreferrer">limit</a>), the decimal representation of <code>d</code> has no significant decimal places. Similarly if <code>(d - round(d)) * 10^n</code> is less than <code>epsilon</code>, d can have at most <code>n</code> significant places. </p> <p>Use <a href="https://stackoverflow.com/users/22656/jon-skeet">Jon Skeet</a>'s <a href="http://pobox.com/~skeet/csharp/DoubleConverter.cs" rel="nofollow noreferrer"><code>DoubleConverter</code></a> to check for the cases where <code>d</code> isn't accurate enough to hold the decimal places you are looking for.</p>
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    1. USCommunity
    1. USDavid Schmitt
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    1. COI also looked at the DoubleConverter Jon posted in his answer and it seems to do pretty much the same as BigDecimal. I wonder why he removed his answer.
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