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    <p>If you're using Cocoa in Python, then you can just do that, as PyObjC imbues <code>NSString</code> with all of the Python <code>unicode</code> class's abilities.</p> <p>Otherwise, there are two ways.</p> <p>One is to create an array with the same string in it <code>n</code> times, and use <code>componentsJoinedByString:</code>. Something like this:</p> <pre><code>NSMutableArray *repetitions = [NSMutableArray arrayWithCapacity:n]; for (NSUInteger i = 0UL; i &lt; n; ++i) [repetitions addObject:inputString]; outputString = [repetitions componentsJoinedByString:@""]; </code></pre> <p>The other way would be to start with an empty <code>NSMutableString</code> and append the string to it <code>n</code> times, like this:</p> <pre><code>NSMutableString *temp = [NSMutableString stringWithCapacity:[inputString length] * n]; for (NSUInteger i = 0UL; i &lt; n; ++i) [temp appendString:inputString]; outputString = [NSString stringWithString:temp]; </code></pre> <p>You may be able to cut out the <code>stringWithString:</code> call if it's OK for you to return a mutable string here. Otherwise, you probably should return an immutable string, and the <code>stringWithString:</code> message here means you have two copies of the string in memory.</p> <p>Therefore, I recommend the <code>componentsJoinedByString:</code> solution.</p> <p>[Edit: Borrowed idea to use <code>…WithCapacity:</code> methods from <a href="https://stackoverflow.com/questions/260945/create-nsstring-by-repeating-another-string-a-given-number-of-times#260969">Mike McMaster's answer</a>.]</p>
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    1. POCreate NSString by repeating another string a given number of times
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    1. USPeter Hosey
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    1. COThanks for the alternative of using componentsJoinedByString.
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      1. USSergio Acosta
    2. COYeah, good suggestion. Probably a teeny bit more efficient that my (admittedly generic) solution.
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      1. USMike McMaster
 

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