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POQuartz scheduler is failing to start the cron job
 

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  1. POQuartz scheduler is failing to start the cron job
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    <p>Hi I am using Quartz scheduler to trigger a cron which needs to perform a host of activities. My Code for the same is as follow:</p> <p>In the init() method of my InitServlet class, I am defining my TimerServer</p> <pre><code> public class InitServlet extends HttpServlet { public void init(ServletConfig config) throws ServletException { try { System.out.println("Starting the CRON"); //Set the DSO Handler CRON TimerServer task = TimerServer.getInstance(); task.setTask(); } catch (Exception ex) { System.out.println("Failed to start the cron"); ex.printStackTrace(); } } </code></pre> <p>In my TimerServer class I have the following methods</p> <pre><code> public void setTask() { try{ this.setSubscriptionDailyJob(); } catch(SchedulerException ex) { log.error("SchedulerException: "+ex.getMessage(), ex); } private void setSubscriptionDailyJob() throws SchedulerException { log.info("Step 1 "); Scheduler scheduler = schedulerFactory.getScheduler(); log.info("Step 2 "); JobDetail subscriptionJob = new JobDetail("subscription", "subscriptiongroup", SubscriptionDaily.class); log.info("Step 3 "); // Initiate CronTrigger with its name and group name CronTrigger subscriptionCronTrigger = new CronTrigger("subscriptionCronTrigger", "subscriptionTriggerGroup"); try { log.info("Subscription cron: "+Constants.SUBSCRIPTION_CRON); // setup CronExpression CronExpression cexp = new CronExpression(Constants.SUBSCRIPTION_CRON); // Assign the CronExpression to CronTrigger subscriptionCronTrigger.setCronExpression(cexp); } catch (Exception ex) { log.warn("Exception: "+ex.getMessage(), ex); } scheduler.scheduleJob(subscriptionJob, subscriptionCronTrigger); scheduler.start(); } </code></pre> <p>In my SubscriptionDaily class :</p> <pre><code>public class SubscriptionDaily implements Job { public void execute(JobExecutionContext arg0) throws JobExecutionException { //Actions to be performed } } </code></pre> <p>Now checking my logs, I am getting Step 1, Step 2 but not further. </p> <p>My code is getting stucked at the TimerServer class itself. Logs wrt to Scheduler are :</p> <pre><code>17:24:43 INFO [TimerServer]: Step 1 17:24:43 INFO [SimpleThreadPool]: Job execution threads will use class loader of thread: http-8080-1 17:24:43 INFO [SchedulerSignalerImpl]: Initialized Scheduler Signaller of type: class org.quartz.core.SchedulerSignalerImpl 17:24:43 INFO [QuartzScheduler]: Quartz Scheduler v.1.6.5 created. 17:24:43 INFO [RAMJobStore]: RAMJobStore initialized. 17:24:43 INFO [StdSchedulerFactory]: Quartz scheduler 'DefaultQuartzScheduler' initialized from default resource file in Quartz package: 'quartz.properties' 17:24:43 INFO [StdSchedulerFactory]: Quartz scheduler version: 1.6.5 17:24:43 INFO [TimerServer]: Step 2 </code></pre> <p>I think a log entry is missing : [QuartzScheduler]: Scheduler DefaultQuartzScheduler_$_NON_CLUSTERED started.</p> <p>Please help. </p>
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