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POHow to change attribute on Scala XML Element
 

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    <p>I have an XML file that I would like to map some attributes of in with a script. For example:</p> <pre><code>&lt;a&gt; &lt;b attr1 = "100" attr2 = "50"/&gt; &lt;/a&gt; </code></pre> <p>might have attributes scaled by a factor of two:</p> <pre><code>&lt;a&gt; &lt;b attr1 = "200" attr2 = "100"/&gt; &lt;/a&gt; </code></pre> <p>This page has a suggestion for <em>adding</em> attributes but doesn't detail a way to map a current attribute with a function (this way would make that very hard): <a href="http://www.scalaclass.com/book/export/html/1" rel="noreferrer">http://www.scalaclass.com/book/export/html/1</a></p> <p>What I've come up with is to manually create the XML (non-scala) linked-list... something like:</p> <pre><code>// a typical match case for running thru XML elements: case Elem(prefix, e, attributes, scope, children @ _*) =&gt; { var newAttribs = attributes for(attr &lt;- newAttribs) attr.key match { case "attr1" =&gt; newAttribs = attribs.append(new UnprefixedAttribute("attr1", (attr.value.head.text.toFloat * 2.0f).toString, attr.next)) case "attr2" =&gt; newAttribs = attribs.append(new UnprefixedAttribute("attr2", (attr.value.head.text.toFloat * 2.0f).toString, attr.next)) case _ =&gt; } Elem(prefix, e, newAttribs, scope, updateSubNode(children) : _*) // set new attribs and process the child elements } </code></pre> <p>Its hideous, wordy, and needlessly re-orders the attributes in the output, which is bad for my current project due to some bad client code. Is there a scala-esque way to do this?</p>
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    1. COI'm shocked at how lousy the library seems to be in this regard.
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      1. USDaniel C. Sobral
 

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