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    <p>You can use <code>printf()</code>, and a special format string:</p> <pre><code>char *str = "0123456789"; printf("%.6s\n", str + 1); </code></pre> <p>The precision in the <code>%s</code> conversion specifier specifies the maximum number of characters to print. You can use a variable to specify the precision at runtime as well:</p> <pre><code>int length = 6; char *str = "0123456789"; printf("%.*s\n", length, str + 1); </code></pre> <p>In this example, the * is used to indicate that the next argument (<code>length</code>) will contain the precision for the <code>%s</code> conversion, the corresponding argument must be an <code>int</code>.</p> <p>Pointer arithmetic can be used to specify the starting position as I did above.</p> <p><strong>[EDIT]</strong></p> <p>One more point, if your string is shorter than your precision specifier, less characters will be printed, for example:</p> <pre><code>int length = 10; char *str = "0123456789"; printf("%.*s\n", length, str + 5); </code></pre> <p>Will print "<code>56789</code>". If you always want to print a certain number of characters, specify both a minimum field width and a precision:</p> <pre><code>printf("%10.10s\n", str + 5); </code></pre> <p>or</p> <pre><code>printf("%*.*s\n", length, length, str + 5); </code></pre> <p>which will print:</p> <pre><code>" 56789" </code></pre> <p>You can use the minus sign to left-justify the output in the field:</p> <pre><code>printf("%-10.10s\n", str + 5); </code></pre> <p>Finally, the minimum field width and the precision can be different, i.e. </p> <pre><code>printf("%8.5s\n", str); </code></pre> <p>will print at most 5 characters right-justified in an 8 character field.</p>
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    1. COThat’s pretty cool. I only learned about the string truncation earlier today (I guess I’ve always just done my substringing with the actual strings instead of `printf`). Now why is that not possible with integers? Why can you not say for example `printf("%.2d", 123);` to print only `23` or `printf("%-.2d", 123);` to print only `12`? `:-|`
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