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POjava phone number validation
 

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    <p>Here is my problem:</p> <p>Create a constructor for a telephone number given a string in the form xxx-xxx-xxxx or xxx-xxxx for a local number. Throw an exception if the format is not valid.</p> <p>So I was thinking to validate it using a regular expression, but I don't know if I'm doing it correctly. Also what kind of exception would I have to throw? Do I need to create my own exception?</p> <pre><code> public TelephoneNumber(String aString){ if(isPhoneNumberValid(aString)==true){ StringTokenizer tokens = new StringTokenizer("-"); if(tokens.countTokens()==3){ areaCode = Integer.parseInt(tokens.nextToken()); exchangeCode = Integer.parseInt(tokens.nextToken()); number = Integer.parseInt(tokens.nextToken()); } else if(tokens.countTokens()==2){ exchangeCode = Integer.parseInt(tokens.nextToken()); number = Integer.parseInt(tokens.nextToken()); } else{ //throw an excemption here } } } public static boolean isPhoneNumberValid(String phoneNumber){ boolean isValid = false; //Initialize reg ex for phone number. String expression = "(\\d{3})(\\[-])(\\d{4})$"; CharSequence inputStr = phoneNumber; Pattern pattern = Pattern.compile(expression); Matcher matcher = pattern.matcher(inputStr); if(matcher.matches()){ isValid = true; } return isValid; } </code></pre> <p>Hi sorry, yes this is homework. For this assignments the only valid format are xxx-xxx-xxxx and xxx-xxxx, all other formats (xxx)xxx-xxxx or xxxxxxxxxx are invalid in this case.</p> <p>I would like to know if my regular expression is correct</p>
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    1. USMichael Myers
    1. USuser69514
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    1. COis this homework? should be tagged as such if so...
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      1. USbrabster
    2. COObvious question: Are you sure that your phone number format catches any variety of phone number that your users might want to enter? Nothing is more frustrating than a half-smart system that refuses to accept perfectly valid data. (Oh, and if this is only homework - never mind.)
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    3. COCompletely agree with @Tomalak. If this is a production system, the correct answer is to strip out any non-numeric characters and validate the resulting number.
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