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    <p>The error is more complex than you would initially think, because it is actually the '+' operator that causes the "possible loss of precision error". The error can be resolved if the cast is moved: </p> <pre><code>s[i] = (char)('A' + (num[i]- 1));</code></pre> <p><br/> <b>Explanation</b> <br/> In the first bullet list of <a href="http://java.sun.com/docs/books/jls/third_edition/html/conversions.html#5.6.2" rel="noreferrer">§5.6.2 Binary Numeric Promotion</a> in the <a href="http://java.sun.com/docs/books/jls/" rel="noreferrer">Java Language Specification</a> it is stated that: </p> <blockquote>When an operator applies binary numeric promotion to a pair of operands [...] the following rules apply, in order, using widening conversion (§5.1.2) to convert operands as necessary:<br/><br/> <ul><li>If any of the operands is of a reference type, unboxing conversion (§5.1.8) is performed. Then:</li> <li>If either operand is of type double, the other is converted to double.</li> <li>Otherwise, if either operand is of type float, the other is converted to float.</li> <li>Otherwise, if either operand is of type long, the other is converted to long.</li> <li><b>Otherwise, both operands are converted to type int.</b></li></ul></blockquote> <p>In the next bullet list it is stated that:</p> <blockquote>Binary numeric promotion is performed on the operands of certain operators:<br/><br/> <ul><li>The multiplicative operators *, / and % (§15.17)</li> <li><b>The addition and subtraction operators for numeric types + and - (§15.18.2)</b></li> <li>The numerical comparison operators , and >= (§15.20.1)</li> <li>The numerical equality operators == and != (§15.21.1)</li> <li>The integer bitwise operators &, ^, and | (§15.22.1)</li> <li>In certain cases, the conditional operator ? : (§15.25)</li></ul></blockquote> <p>In your case, that translates to: <pre><code>s[i] = (int)'A' + (int)((char)(num[i] - (int)1));</code></pre>hence the error.<br/> </p>
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