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PODelete / Remove node from XPathNodeIterator, given an XPath
 

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  1. PODelete / Remove node from XPathNodeIterator, given an XPath
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    <p>First of all, if someone has a different, perhaps shorter (or better), solution to the problem, it's welcome as well.</p> <hr> <p>I'm trying to "simply" remove (almost) duplicate elements in XSLT. There's some (metadata) nodes i don't want to include when comparing, and i couldn't figure out how do do that in XSLT so thought i'd extend it with a function removing these nodes. Like so:</p> <pre><code>&lt;xsl:for-each select="abx:removeNodes(d/df600|d/df610|d/df611|d/df630|d/df650|d/df651|d/df655, '*[@key=&amp;quot;i1&amp;quot; or @key=&amp;quot;i2&amp;quot; or key=&amp;quot;db&amp;quot;]')"&gt; &lt;xsl:if test="not(node()=preceding-sibling::*)"&gt; blah &lt;/xsl:if&gt; &lt;/xsl:for-each&gt; </code></pre> <p>And the extension, which doesn't work so well... (C#)</p> <pre><code>public XPathNodeIterator removeNodes(XPathNodeIterator p_NodeIterator, String removeXPath) { Logger Logger = new Logger("xslt"); Logger.Log("removeNodes(removeXPath={0}):", removeXPath); foreach (XPathNavigator CurrentNode in p_NodeIterator) { Logger.Log("removeNodes(): CurrentNode.OuterXml={0}.", CurrentNode.OuterXml); foreach (XPathNavigator CurrentSubNode in CurrentNode.Select(removeXPath)) { Logger.Log("removeNodes(): CurrentSubNode.OuterXml={0}.", CurrentSubNode.OuterXml); // How do i delete this node!? //CurrentSubNode.DeleteSelf(); } } return p_NodeIterator; } </code></pre> <p>My initial approach using 'CurrentSubNode.DeleteSelf();' doesn't work because it gets confused and loses its position in the XPathNavigator, causing it to only delete the first item it finds using "removeXPath". Something like a DeleteAndMoveNext() would be nice but there seems to be no such method...</p> <hr> <p>Example data:</p> <pre><code>&lt;df650&gt; &lt;df650 key="i1"&gt; &lt;/df650&gt; &lt;df650 key="i2"&gt;0&lt;/df650&gt; &lt;df650 key="a"&gt;foo&lt;/df650&gt; &lt;df650 key="x"&gt;bar&lt;/df650&gt; &lt;df650 key="db"&gt;someDB&lt;/df650&gt; &lt;df650 key="id"&gt;b2&lt;/df650&gt; &lt;df650 key="dsname"&gt;someDS&lt;/df650&gt; &lt;/df650&gt; </code></pre> <p>..and then another identical node (if you ignore the meta fields; db,id,dsname).</p> <pre><code>&lt;df650&gt; &lt;df650 key="i1"&gt; &lt;/df650&gt; &lt;df650 key="i2"&gt;0&lt;/df650&gt; &lt;df650 key="a"&gt;foo&lt;/df650&gt; &lt;df650 key="x"&gt;bar&lt;/df650&gt; &lt;df650 key="db"&gt;someOtherDB&lt;/df650&gt; &lt;df650 key="id"&gt;b2&lt;/df650&gt; &lt;df650 key="dsname"&gt;someOtherDS&lt;/df650&gt; &lt;/df650&gt; </code></pre> <p>The result should be...</p> <pre><code>&lt;df650&gt; &lt;df650 key="i1"&gt; &lt;/df650&gt; &lt;df650 key="i2"&gt;0&lt;/df650&gt; &lt;df650 key="a"&gt;foo&lt;/df650&gt; &lt;df650 key="x"&gt;bar&lt;/df650&gt; &lt;/df650&gt; </code></pre>
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