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    <p>Assuming you are <em>only</em> looking for simple obfuscation that will obscure things from the <em>very</em> casual observer, and you aren't looking to use third party libraries. I'd recommend something like the Vigenere cipher. It is one of the strongest of the simple ancient ciphers.</p> <p><a href="https://en.wikipedia.org/wiki/Vigen%C3%A8re_cipher" rel="noreferrer">Vigenère cipher</a></p> <p>It's quick and easy to implement. Something like:</p> <pre><code>import base64 def encode(key, string): encoded_chars = [] for i in xrange(len(string)): key_c = key[i % len(key)] encoded_c = chr(ord(string[i]) + ord(key_c) % 256) encoded_chars.append(encoded_c) encoded_string = "".join(encoded_chars) return base64.urlsafe_b64encode(encoded_string) </code></pre> <p>Decode is pretty much the same, except you subtract the key.</p> <p>It is much harder to break if the strings you are encoding are short, and/or if it is hard to guess the length of the passphrase used. </p> <p>If you are looking for something cryptographic, PyCrypto is probably your best bet, though previous answers overlook some details: ECB mode in PyCrypto requires your message to be a multiple of 16 characters in length. So, you must pad. Also, if you want to use them as URL parameters, use <code>base64.urlsafe_b64_encode()</code>, rather than the standard one. This replaces a few of the characters in the base64 alphabet with URL-safe characters (as it's name suggests).</p> <p>However, you should be ABSOLUTELY certain that this <em>very</em> thin layer of obfuscation suffices for your needs before using this. The Wikipedia article I linked to provides detailed instructions for breaking the cipher, so anyone with a moderate amount of determination could easily break it.</p>
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    1. POSimple way to encode a string according to a password?
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    1. COThe Vignere method looks like a great fit for my needs. Pointing out how to make the hashes URL-safe is the cherry on top. Perfect.
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    2. COlocal variable 'encoded_c' referenced before assignment. I don't really understand the code yet so I can't really fix it myself, sadly.
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    3. COI fixed smehmood's script, and added the decoding function https://gist.github.com/ilogik/6f9431e4588015ecb194
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