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2010-03-18T22:18:31.317
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The way you are looping through the array, using : <pre><code>foreach($array as $var => $content) { // ... } </code></pre> makes me think you should use an associative array for your <code>$array</code>. i.e., it should be declared this way : <pre><code>$array = array("HEADER" => "Welcome to ".NAME."'s website!"); </code></pre> And, as a demonstration, here's an example of code : <pre><code>$template = <<<TPL Hello, World ! {HEADER} And here's the content ;-) TPL; define("NAME","Site Name"); $array = array("HEADER" => "Welcome to ".NAME."'s website!"); foreach($array as $var => $content) { $template = str_replace("{" . strtoupper($var). "}", $content,$template); } var_dump($template); </code></pre> And the output I get it : <pre><code>string 'Hello, World ! Welcome to Site Name's website! And here's the content ;-)' (length=73) </code></pre> Which indicates it's working ;-) (It wasn't, when <code>$array</code> was declared the way you set it) When using this : <pre><code>$array = array("HEADER","This is the header"); var_dump($array); </code></pre> You are declaring an array that contains two items : <pre><code>array 0 => string 'HEADER' (length=6) 1 => string 'This is the header' (length=18) </code></pre> On the other hand, when using this : <pre><code>$array = array("HEADER" => "This is the header"); var_dump($array); </code></pre> You are declaring an array that : <ul> <li>contains only one item</li> <li>"HEADER" being the key</li> <li>and "This is the header" being the value</li> </ul> Which gives : <pre><code>array 'HEADER' => string 'This is the header' (length=18) </code></pre> When using <code>foreach ($array as $key => $value)</code>, you need the second one ;-) And, purely for reference, you can take a look at, in the manual, the following pages : <ul> <li><a href="http://fr2.php.net/manual/en/language.types.array.php" rel="nofollow noreferrer">Arrays</a></li> <li><a href="http://fr.php.net/manual/en/control-structures.foreach.php" rel="nofollow noreferrer">foreach</a></li> </ul>
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1. POphp define variable inside str_replace array
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1. USPascal MARTIN
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1. COmy bad i am using that sort of array, i just typed it on the fly here. yes i know how to use arrays and foreach..
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2. COdoes this mean your problem is solved ? Or is there still something that *doesn't work* ? If so, can you edit your question to add some informations to say more about what *doesn't work* mean ?
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