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    1. COIf I understand what you're saying, your answer would work in a case like this: B D G G G G G G G G G G G S Z Lower half: B D G G G G G -> B D G where mid + 1 would be the min index. Upper half: G G G G G S Z -> G S Z where mid - 1 would be the max index. Is this right? If it is though, I'm not sure it would work in this case: B D E F G G G G G H Q R S S Z Lower half: B D E F G G G -> G G G where Mid - 1 would have to be the min index. Upper half: G H Q R S S Z -> G H Q where mid - 2 would have to be the upper index. Am I understanding what you said, correctly?
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      1. USaloh
    2. CONo. Using your example to clarify: B D G G G G G G G G G G G S Z mid = G (index 7), now check the top half G G G G G S Z. mid = G (index 11), now check the top half G S Z. mid = S, not G, so check the bottom half G mid = G (index 12), and since there is no more to check, index 12 gives us our maximum index. Now we repeat this process on the lower half and get that the minimum index is 2. Then we know that the indices between 2 and 12 inclusive are all G.
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      1. USMBennett
    3. COThank you. I understand now with the example you used. However, what about with the second example? B D E F G G G G G H Q R S S Z. Upper half: G H Q R S S Z mid = R, -> check G H Q mid = H, -> G so max index would be 8. However, for the bottom half: B D E F G G G mid = F, -> check G G G mid = G. In this case the mid is a match but it is not the min index. Or, maybe I am doing something wrong... :(
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      1. USShrimpCrackers
 

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