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    <p>I've just set up a quick benchmarking exercise:</p> <pre><code>Function time to run 1 million iterations -------------------------------------------- (int) "123": 0.55029 intval("123"): 1.0115 (183%) (int) "0": 0.42461 intval("0"): 0.95683 (225%) (int) int: 0.1502 intval(int): 0.65716 (438%) (int) array("a", "b"): 0.91264 intval(array("a", "b")): 1.47681 (162%) (int) "hello": 0.42208 intval("hello"): 0.93678 (222%) </code></pre> <p>On average, calling intval() is two and a half times slower, and the difference is the greatest if your input already is an integer.</p> <p>I'd be interested to know <em>why</em> though.</p> <hr> <p>Update: I've run the tests again, this time with coercion <code>(0 + $var)</code></p> <pre><code>| INPUT ($x) | (int) $x |intval($x) | 0 + $x | |-----------------|------------|-----------|-----------| | "123" | 0.51541 | 0.96924 | 0.33828 | | "0" | 0.42723 | 0.97418 | 0.31353 | | 123 | 0.15011 | 0.61690 | 0.15452 | | array("a", "b") | 0.8893 | 1.45109 | err! | | "hello" | 0.42618 | 0.88803 | 0.1691 | |-----------------|------------|-----------|-----------| </code></pre> <p><strong>Addendum:</strong> I've just come across a slightly unexpected behaviour which you should be aware of when choosing one of these methods:</p> <pre><code>$x = "11"; (int) $x; // int(11) intval($x); // int(11) $x + 0; // int(11) $x = "0x11"; (int) $x; // int(0) intval($x); // int(0) $x + 0; // int(17) ! $x = "011"; (int) $x; // int(11) intval($x); // int(11) $x + 0; // int(11) (not 9) </code></pre> <p><sub>Tested using PHP 5.3.1</sub></p>
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    1. COIt's probably got something to do with the fact that intval() invokes a function call, whilst the cast is handled directly in the interpreter's expression calculator. This may also be the reason a co-ercion is even faster.
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    2. COYour coercion example can be further simplified by using php's little known unary plus operator. $x + 0 -> +$x
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