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    <p>Easiest way would be to get a timestamp that corresponds to today, using the <a href="http://www.php.net/time" rel="nofollow noreferrer"><code>time()</code></a> function ; and 7 times remove 1 day to that timestamp, each echoing the date that corresponds to that timestamp :</p> <pre><code>$timestamp = time(); for ($i = 0 ; $i &lt; 7 ; $i++) { echo date('Y-m-d', $timestamp) . '&lt;br /&gt;'; $timestamp -= 24 * 3600; } </code></pre> <p>Which will get you this output :</p> <pre><code>2010-02-25 2010-02-24 2010-02-23 2010-02-22 2010-02-21 2010-02-20 2010-02-19 </code></pre> <p>Because a timestamp only represents the number of seconds since <code>1970-01-01</code>, substracting one day to a timestamp means substracting <code>24*3600</code> seconds.</p> <hr> <p><strong>Edit after the comments :</strong> </p> <p>For month and weeks changes, this will still work : one day is still 24*3600 seconds.</p> <p>For instance, if you test using this line instead of the first one I posted in my first example :</p> <pre><code>$timestamp = strtotime('2010-02-03'); </code></pre> <p>You'll get this output :</p> <pre><code>2010-02-03 2010-02-02 2010-02-01 2010-01-31 2010-01-30 2010-01-29 2010-01-28 </code></pre> <p>It changed of month fine.</p> <p><br> For leap years, if I test using this :</p> <pre><code>$timestamp = strtotime('2008-03-03'); </code></pre> <p>I get :</p> <pre><code>2008-03-03 2008-03-02 2008-03-01 2008-02-29 2008-02-28 2008-02-27 2008-02-26 </code></pre> <p>Which looks fine, as there were 29 days in february 2008.</p> <p>And if I test with :</p> <pre><code>$timestamp = strtotime('2009-03-03'); </code></pre> <p>I get :</p> <pre><code>2009-03-03 2009-03-02 2009-03-01 2009-02-28 2009-02-27 2009-02-26 2009-02-25 </code></pre> <p>Which looks fine too.</p>
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    1. COthis won't handle leap years
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    2. COand what about the month and week change...?
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    3. CO@Allain and @Anurag : I've edited my post to give a couple of other examples ;; do you have a specific case in which this doesn't work ?
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