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POWriting a C++ version of the algebra game 24
 

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  1. POWriting a C++ version of the algebra game 24
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    <p>I am trying to write a C++ program that works like the game 24. For those who don't know how it is played, basically you try to find any way that 4 numbers can total 24 through the four algebraic operators of +, -, /, *, and parenthesis. </p> <p>As an example, say someone inputs 2,3,1,5 ((2+3)*5) - 1 = 24</p> <p>It was relatively simple to code the function to determine if three numbers can make 24 because of the limited number of positions for parenthesis, but I can not figure how code it efficiently when four variables are entered.</p> <hr> <p>I have some permutations working now but I still cannot enumerate all cases because I don't know how to code for the cases where the operations are the same.</p> <p>Also, what is the easiest way to calculate the RPN? I came across many pages such as this one: <a href="http://www.dreamincode.net/forums/index.php?showtopic=15406" rel="nofollow noreferrer">http://www.dreamincode.net/forums/index.php?showtopic=15406</a> but as a beginner, I am not sure how to implement it.</p> <pre><code>#include &lt;iostream&gt; #include &lt;vector&gt; #include &lt;algorithm&gt; using namespace std; bool MakeSum(int num1, int num2, int num3, int num4) { vector&lt;int&gt; vi; vi.push_back(num1); vi.push_back(num2); vi.push_back(num3); vi.push_back(num4); sort(vi.begin(),vi.end()); char a1 = '+'; char a2 = '-'; char a3 = '*'; char a4 = '/'; vector&lt;char&gt; va; va.push_back(a1); va.push_back(a2); va.push_back(a3); va.push_back(a4); sort(va.begin(),va.end()); while(next_permutation(vi.begin(),vi.end())) { while(next_permutation(va.begin(),va.end())) { cout&lt;&lt;vi[0]&lt;&lt;vi[1]&lt;&lt;vi[2]&lt;&lt;vi[3]&lt;&lt; va[0]&lt;&lt;va[1]&lt;&lt;va[2]&lt;&lt;endl; cout&lt;&lt;vi[0]&lt;&lt;vi[1]&lt;&lt;vi[2]&lt;&lt;va[0]&lt;&lt; vi[3]&lt;&lt;va[1]&lt;&lt;va[2]&lt;&lt;endl; cout&lt;&lt;vi[0]&lt;&lt;vi[1]&lt;&lt;vi[2]&lt;&lt;va[0]&lt;&lt; va[1]&lt;&lt;vi[3]&lt;&lt;va[2]&lt;&lt;endl; cout&lt;&lt;vi[0]&lt;&lt;vi[1]&lt;&lt;va[0]&lt;&lt;vi[2]&lt;&lt; vi[3]&lt;&lt;va[1]&lt;&lt;va[2]&lt;&lt;endl; cout&lt;&lt;vi[0]&lt;&lt;vi[1]&lt;&lt;va[0]&lt;&lt;vi[2]&lt;&lt; va[1]&lt;&lt;vi[3]&lt;&lt;va[2]&lt;&lt;endl; } } return 0; } int main() { MakeSum(5,7,2,1); return 0; } </code></pre>
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    1. CO(2*3*5) + 1 = 24?
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    2. COmost likely ((2+3)*5)+1=24. Good eyes :D
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    3. COBy which you mean ((2+3)*5-1=24 :p There's a ton of other solutions to that particular set of four numbers as well, but yeah.
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