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2010-02-10T21:49:58.647
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2010-02-10T21:49:58.647
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47
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Maxwell Troy Milton King is right, but since his answer is a bit short, I'll post this as well and provide some examples to illustrate. First, the <code>.</code> meta character by default does NOT match line breaks. This is true for many regex implementations, including PHP's flavour. That said, take the text: <pre><code>$text = "Line 1\nLine 2\nLine 3"; </code></pre> and the regex <pre><code>'/.*/' </code></pre> then the regex will only match <code>Line 1</code>. See for yourself: <pre><code>preg_match('/.*/', $text, $match); echo $match[0]; // echos: 'Line 1' </code></pre> since the <code>.*</code> "stops matching" at the <code>\n</code> (new line char). If you want to let it match line breaks as well, append the s-modifier (aka DOT-ALL modifier) at the end of your regex: <pre><code>preg_match('/.*/s', $text, $match); echo $match[0]; // echos: 'Line 1\nLine 2\nLine 3' </code></pre> Now about the m-modifier (multi-line): that will let the <code>^</code> match not only the start of the input string, but also the start of each line. The same with <code>$</code>: it will let the <code>$</code> match not only the end of the input string, but also the end of each line. An example: <pre><code>$text = "Line 1\nLine 2\nLine 3"; preg_match_all('/[0-9]$/', $text, $matches); print_r($matches); </code></pre> which will match only the 3 (at the end of the input). But: but enabling the m-modifier: <pre><code>$text = "Line 1\nLine 2\nLine 3"; preg_match_all('/[0-9]$/m', $text, $matches); print_r($matches); </code></pre> all (single) digits at the end of each line ('1', '2' and '3') are matched.
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1. POphp preg_replace regex that matches multiple lines
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1. USBart Kiers
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