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POGetting some elements in a string using a regex
 

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  1. POGetting some elements in a string using a regex
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    <h2>Context</h2> <hr> <p>Using Ruby I am parsing strings looking like this:</p> <p>A type with an ID...</p> <pre><code>[Image=4b5da003ee133e8368000002] [Video=679hfpam9v56dh800khfdd32] </code></pre> <p>...with between 0 and n additional options separated with @...</p> <pre><code>[Image=4b5da003ee133e8368000002@size:small] [Image=4b5da003ee133e8368000002@size:small@media:true] </code></pre> <p>In this example:</p> <pre><code>[Image=4b5da003ee133e8368000002@size:small@media:true] </code></pre> <p>I want to retrieve:</p> <ol> <li>[Image=4b5da003ee133e8368000002@size:small@media:true]</li> <li>Image</li> <li>4b5da003ee133e8368000002</li> <li>size:small</li> <li>media:true</li> </ol> <h2>Problem</h2> <hr> <p>Right now using this regex:</p> <pre><code>(\[([a-zA-Z]+)=([a-zA-Z0-9]+)(@[a-zA-Z]+:[a-zA-Z]+)*\]) </code></pre> <p>I get...</p> <ol> <li>[Image=4b5da003ee133e8368000002@size:small@media:true]</li> <li>Image</li> <li>4b5da003ee133e8368000002</li> <li>@media:true</li> </ol> <p>What am I doing wrong? How can I get what I want? </p> <p><em>PS: All the results are copied from <a href="http://rubular.com/" rel="nofollow noreferrer">http://rubular.com/</a> which is nice to debug regex. Please use it if it can help you help me :)</em></p> <hr> <p>Edit : if it's impossible to get all options separated, how could I get this:</p> <ol> <li>[Image=4b5da003ee133e8368000002@size:small@media:true]</li> <li>Image</li> <li>4b5da003ee133e8368000002</li> <li>@size:small@media:true</li> </ol>
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    1. COYour edited question is actually pretty easy. Since you've already matched up to the first `@`, you then just need to take everything after that. `(\[([a-zA-Z]+)=([a-zA-Z0-9]+)((?:[^\]])*)\])` seems to give the desired effect.
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    2. CO@mmyers: yes an answer is correct. I'd prefer if someone could give me a solution without the edit though, but if it is impossible...
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