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    <p>If you're doing this type of character interrogation often in a loop, you may not want to use a regexp at all but craft your own search routine interrogating a StringBuffer.</p> <pre><code>/** * Method to evaluate a String to see whether it contains one (or potentially more) of a * char or member of a group of chars. * * @param String to evaluate * * @param String containing all characters to evaluate against the subject string * * @return true on first correct match, false if no match found **/ public boolean sbContainsOneOf(String sStringToCheck, String sCheck) { StringBuffer sb = new StringBuffer(sStringToCheck); char[] tmp2 = sCheck.toCharArray(); for (int i = 0; i &lt; sb.length(); i++) { for (int k = 0; k &lt; tmp2.length; k++) if (sb.charAt(i) == tmp2[k]) { return true; } } return false; } </code></pre> <p>Then all you need to do is call it:</p> <pre><code>String password = "s8bgBQYPmUaNjkToXCJLAwAA"; System.out.println(sbContainsOneOf(password,"0123456789")); </code></pre> <p>It's between 10 and 15 times faster doing it this way.... The longer your String &amp; option list the bigger the difference between the two becomes. Generally I avoid regexps unless they're one offs or spectacularly complex to implement as code and prefer to rep them with optimised StringBuffer-based routines. Doing it this way, gradually your collection of regexp replacements fills up and you end up with a very useable way of pattern interrogation without the high associated regexp overheads.</p>
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    1. POJava Regex Match Error
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