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POWhy is the ELF execution entry point virtual address of the form 0x80xxxxx and not zero 0x0?
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2187484
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2
ClosedDate
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1
CommunityOwnedDate
CreationDate
2010-02-02T20:33:57.533
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12
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2017-08-30T13:34:38.950
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2017-08-30T13:34:38.950
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264704
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Score
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text
Body
When executed, program will start running from virtual address 0x80482c0. This address doesn't point to our <code>main()</code> procedure, but to a procedure named <code>_start</code> which is created by the linker. My Google research so far just led me to some (vague) historical speculations like this: <blockquote> There is folklore that 0x08048000 once was STACK_TOP (that is, the stack grew downwards from near 0x08048000 towards 0) on a port of *NIX to i386 that was promulgated by a group from Santa Cruz, California. This was when 128MB of RAM was expensive, and 4GB of RAM was unthinkable. </blockquote> Can anyone confirm/deny this?
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<point><elf><virtual-address-space>
Title
Why is the ELF execution entry point virtual address of the form 0x80xxxxx and not zero 0x0?
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1. USPaolo Forgia
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1. USMichael L.
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