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    <p>You can remove all those from the buffer with this command:</p> <pre><code>:%s!&lt;swf.\{-}/swf&gt;!! </code></pre> <p>if you also have tags that might be split on two lines, you can add the <code>\_</code> modifier to make <code>.</code> match newlines too:</p> <pre><code>:%s!&lt;swf\_.\{-}/swf&gt;!! </code></pre> <p>this assuming you want to remove both the tags and what they contain, if you just want to get rid of the tags and keep the content</p> <pre><code>:%s!&lt;/\?swf.\{-}&gt;!! </code></pre> <p>Notes:</p> <ul> <li>you don't need to escape <code>&lt;</code> or <code>&gt;</code></li> <li>you can choose whatever pattern delimiter you wish: Vim will use the first character you put after the <code>s</code> in the substitute command: this takes away the need to escape forward slashes in your pattern</li> </ul> <p>EDIT: extending my answer after your comment</p> <ul> <li>this is exactly like /STRING/REPLACE/g I only used a <code>!</code> instead of <code>/</code> so that I don't have to quote the backslash in the pattern (see my second point above)</li> <li>I didn't add the <code>g</code> modifier at the end since I have <code>:set gdefault</code> in my <code>.vimrc</code> since forever (it means that by default Vim will substitute all matches in a line instead of just the first, thus reverting the meaning of <code>/g</code>)</li> <li><code>\{-}</code> is the "ungreedy" version of the <code>*</code> quantifier, i.e. it matches 0 or more of the preceding atom but take <strong>as few as possible</strong> -- this helps you make sure that your search pattern will extend to the first "closing tag" instead of the last.</li> </ul> <p>HTH</p>
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    1. COThank you thank you, that works a treat!! I'm curious though, how does this work without using /STRING/REPLACE/g format? And what does the {-} mean?
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    2. COUpdated my answer with details about your comment
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    3. COAwsome, thanks alot!!
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