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    <p>This all depends on your interpretation of <em>what</em> an "outlier" is. A common approach: </p> <ul> <li>High outliers are anything beyond the 3rd quartile + 1.5 * the inter-quartile range (IQR)</li> <li>Low outliers are anything beneath the 1st quartile - 1.5 * IQR</li> </ul> <p>This is also the approach described by <a href="http://mathworld.wolfram.com/Outlier.html" rel="nofollow noreferrer">Wolfram's Mathworld</a>.</p> <p>This is easily wrapped up in a function :) I've tried to write the below clearly; obvious refactoring opportunities do exist. <strong>Note that your given sample contains no outlying values using this common approach</strong>.</p> <pre><code>function filterOutliers(someArray) { // Copy the values, rather than operating on references to existing values var values = someArray.concat(); // Then sort values.sort( function(a, b) { return a - b; }); /* Then find a generous IQR. This is generous because if (values.length / 4) * is not an int, then really you should average the two elements on either * side to find q1. */ var q1 = values[Math.floor((values.length / 4))]; // Likewise for q3. var q3 = values[Math.ceil((values.length * (3 / 4)))]; var iqr = q3 - q1; // Then find min and max values var maxValue = q3 + iqr*1.5; var minValue = q1 - iqr*1.5; // Then filter anything beyond or beneath these values. var filteredValues = values.filter(function(x) { return (x &lt;= maxValue) &amp;&amp; (x &gt;= minValue); }); // Then return return filteredValues; } </code></pre>
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