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  1. PO
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    <h2>The basic idea</h2> <p>You could sum all the numbers and then subtract the largestOne in the end</p> <pre><code>for (var i = 0; i &lt; arr.length; i += 1) { if (arr[i] &gt; largestNumber) { largestNumber = arr[i]; } sumTotal += arr[i]; } // now because the sumTotal includes the largestNumberAlso // to get the same result as in your code, you have to sumTotal -= largestNumber </code></pre> <h2>The whole code altogether</h2> <pre><code>var myArray = [4, 6, 24, 10, 1, 3]; var arrayAddition = function (arr) { var largestNumber = arr[0]; var sumTotal = 0; for (var i = 0; i &lt; arr.length; i += 1) { if (arr[i] &gt; largestNumber) { largestNumber = arr[i]; } sumTotal += arr[i]; } sumTotal -= largestNumber; if (largestNumber === sumTotal) { return 'The result is true because the sumTotal is ' + sumTotal + ' and the largestNumber is ' + largestNumber; } else { return 'Wrong, the sumtotal is ' + sumTotal + ' and the the largestNumber is ' + largestNumber; } }; </code></pre> <h2>Some small improvement</h2> <p>There is one more improvement to make your code slightly faster</p> <p>Instead of doing the loop like this</p> <pre><code>for( var i = 0; i &lt; arr.length; i += 1 ) { ... } </code></pre> <p>You can write it like this</p> <pre><code>for( var i = 0, len = arr.length; i &lt; len; i++ ) { ... } </code></pre> <p>And that way you can save some processor cycles because you don't need to lookup the length attribute every time</p> <h2>Some other funky improvement</h2> <pre><code>var myArray = [4, 6, 24, 10, 1, 3]; var arrayAddition = function (arr) { var largestNumber = arr[0]; // that could satisfy the equation var sumTotal = 0; for( var i = 0, len = arr.length; i &lt; len; i++ ) // change it only if it is bigger then the current sum, // this way the largest number may be incorect if it is // smaller then the sum, but we don't care for that // on the other hand we can save some cpu cycles by not // doing a 'largestNumber = arr[i]' operation // if we don't really need to if (arr[i] &gt; sumTotal) { largestNumber = arr[i]; } sumTotal += arr[i]; } sumTotal -= largestNumber; if (largestNumber === sumTotal) { return 'The result is true because the sumTotal is ' + sumTotal + ' and the largestNumber is ' + largestNumber; } else { return 'Wrong, the sumtotal is ' + sumTotal + ' and the the largestNumber is ' + largestNumber; } }; </code></pre>
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    1. POloop over array, find largest number and see if all other numbers equal it in javascript
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    1. USIgor Šarčević
    1. USIgor Šarčević
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    1. COI noticed that @meiamsome put the `sumTotal += arr[i];` inside the if statement where as you put it outside. Any reason why one would be better over the other?
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      1. USjstone
    2. COI think he edited his answer, because it is now outside. Anyway if you would put it inside the if, the algorithm would not work.
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      1. USIgor Šarčević
    3. COAlso worth noting that this algorithm can be even more optimized if you put an upper limit on the numbers in the array
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      1. USIgor Šarčević
 

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