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    <p>Your options are to return by value or to return a reference/pointer to a heap-based object.</p> <h2>Return by value</h2> <p>Changing your function signature to this</p> <pre><code>Test returnval() </code></pre> <p>will copy <code>obj</code>. Note that the pointers you print out may still have the same value for the object inside the class and the object outside, as the compiler may have performed a <a href="http://cpp-next.com/archive/2009/08/want-speed-pass-by-value/" rel="nofollow noreferrer">return value optimisation</a>.</p> <p>If the <code>Test</code> class is not managing dynamically allocated resources, then you can rely on the automatically created copy constructors that the compiler will inject. If <code>Test</code> has dynamically allocated data, then you must write your own. See <a href="https://stackoverflow.com/questions/4172722/what-is-the-rule-of-three">What is the Rule of Three?</a>.</p> <h2>Return a pointer (or reference) to a heap-based object</h2> <p>You can change it to a heap-based object by using <code>new</code>, and then return a pointer instead: </p> <pre><code>Test* returnptr(){ Test* obj = new Test(9,9); cout &lt;&lt; "in function: " &lt;&lt; obj &lt;&lt; endl; return obj; } </code></pre> <p>Or better yet, a smart pointer like shared_ptr to manage the deletion for you:</p> <pre><code>shared_ptr&lt;Test&gt; returnptr() { // Wrapping the pointer in a shared_ptr will ensure it gets cleaned // up automatically when the last reference to it (usage of it) // goes out of scope. shared_ptr&lt;Test&gt; obj(new Test(9,9)); cout &lt;&lt; "in function: " &lt;&lt; obj.get() &lt;&lt; endl; return obj; } </code></pre> <h2>Final note</h2> <p>As pointed out by one of the commenters on my answer, in C++11, you have further options to control how the temporary object from your function is returned by providing move constructors for <code>Test</code> and using <code>std::move</code> as necessary. This is a fairly meaty subject, but you can read more about it at the following links:</p> <ul> <li><a href="https://stackoverflow.com/questions/3106110/what-is-move-semantics">What is move semantics?</a></li> <li><a href="http://blogs.msdn.com/b/vcblog/archive/2009/02/03/rvalue-references-c-0x-features-in-vc10-part-2.aspx" rel="nofollow noreferrer">Rvalue References: C++0x Features in VC10</a></li> <li><a href="http://www.artima.com/cppsource/rvalue.html" rel="nofollow noreferrer">A Brief Introduction to Rvalue References</a></li> </ul>
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    1. POReturning a reference - why my code works properly? It shouldn't
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    1. COYou forgot you can also "move" the object. So `return std::move(SomeObject);` also works.
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    2. CO@CantChooseUsernames - Yup. Thanks for pointing it out.
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