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POFind frequency of array strings in a file sized string, using Python
 

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  1. POFind frequency of array strings in a file sized string, using Python
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    <p>I've looked at a lot of answers, which are aimed at finding the occurrence of every word in the file, or big string or even arrays. but I don't want to do this, nor are my strings coming from a text file.</p> <p>Given a big string, like a file sized string how would you count the frequency of each array element in the big string - including spaces within words?</p> <pre><code>def calculate_commonness(context, links): c = Counter() content = context.translate(string.maketrans("",""), string.punctuation).split(None) for word in content: if word in links: c[word] += 1 print c context = "It was November. Although it was November November November Passage not yet late, the sky was dark when I turned into Laundress Passage. Father had finished for the day, switched off the shop lights and closed the shutters; but so I would not come home to darkness he had left on the light over the stairs to the flat. Through the glass in the door it cast a foolscap rectangle of paleness onto the wet pavement, and it was while I was standing in that rectangle, about to turn my key in the door, that I first saw the letter. Another white rectangle, it was on the fifth step from the bottom, where I couldn\'t miss it." links = ['November', 'Laundress', 'Passage', 'Father had'] # My output should look (something) like this: # November = 4 # Laundress = 1 # Passage = 2 # Father had = 1 </code></pre> <p>At the moment it's finding November, Laundress and Passage but not 'Father had'. I need to be able to find string elements with spaces. I know this is because I'm splitting the context by " " which is returning "Father" "had", so how do I split context appropriately or do I use this with regex findall? </p> <p>EDIT: Using context as a big string I have:</p> <pre><code> for l in links: c[l] = context.lower().count(l) print c </code></pre> <p>returns:</p> <pre><code>Counter({'Laundress': 0, 'November': 0, 'Father had': 0, 'Passage': 0}) </code></pre>
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    1. COWhat if some of the links are substrings of (concatenation of) others? E.g. `links = ['day', 'mayday', 'today']`.
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    2. COThen I shouldn't be counting them. So in that case day should be returned as once. It should match links exactly.
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    3. COMaybe I gave a wrong example, what about `links = ['November', 'was November']`? Is the result `{November: 4, was November: 2}` or `{November: 2, was November: 2}`?
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