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2013-12-24T10:28:24.753
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<p>Please see the follwing pseudocode. This works fine with 32 bit inputs.</p> <h1>code</h1> <pre><code>#include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> #define USERSIZE 128 long long int bin2dec(long long int ip) { int count, calc; long long int add = 0; for (count = 0; count < 64; count++) calc = ip%10; add += pow(2, count) * calc; ip = ip/10; if (ip == 0) break; } return add; } int main() { int len = -1, maskval = -1; long long int temp; long long int intLeft; long long int intRight; char * input, *left, *right; input = calloc (USERSIZE, sizeof *input); left = calloc (USERSIZE/2, sizeof *left); right = calloc (USERSIZE/2, sizeof *right); printf("Enter the number in binary\n"); scanf("%s", input); len = strlen (input); if (len> 0) { if (len%2 == 0) { maskval = len/2; strncpy(left, input, maskval); temp = atoll(left); intLeft = bin2dec(temp); printf("left = %lld (%lld)\n", intLeft, temp); input += maskval; strncpy(right, input, maskval); temp = atoll(right); intRight = bin2dec(temp); printf("right = %lld (%lld)\n", intRight, temp); } else printf("This number does not have even number of bits, pleease add a 0 before the number and enter again\n"); } else printf("Enter a valid string\n"); return 0; #endif } </code></pre> <h1>output</h1> <pre><code>[sourav@infba01383 so_overflow]# ./a.out Enter the number in binary 100 This number does not have even number of bits, pleease add a 0 before the number and enter again [sourav@infba01383 so_overflow]# ./a.out Enter the number in binary 0100 left = 1 (1) right = 0 (0) [sourav@infba01383 so_overflow]# ./a.out Enter the number in binary 1000 left = 2 (10) right = 0 (0) [sourav@infba01383 so_overflow]# ./a.out Enter the number in binary 0000 left = 0 (0) right = 0 (0) [sourav@infba01383 so_overflow]# ./a.out Enter the number in binary 1111 left = 3 (11) right = 3 (11) [sourav@infba01383 so_overflow]#./a.out Enter the number in binary 11111111111111111111111111111111 left = 65535 (1111111111111111) right = 65535 (1111111111111111) [sourav@infba01383 so_overflow]# </code></pre> <p>Beware!!! there is no check for the validity of the inputs.</p>
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1. POwhat is the elegant way of dividing input bitstring into two halves
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1. USSourav Ghosh
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