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    <p>You shouldn't use keywords such as "Integer" for variable identifiers.</p> <p>There are some lingering questions I have, but I would simply use Java's builtin <strong>split()</strong> function on strings and use <strong>regex</strong> to split the string into significant figures (ignoring ending and leading zeroes). Then return the sum of the length of the strings . Here is the code for pure integers.</p> <pre><code>String myint = "000100101111220000020000"; String[] sig_figs = myint.split("(^0+|0+$)"); int sum = 0; for(String fig : sig_figs) { sum += fig.length(); } return sum; </code></pre> <p>If we include floats, there are other rules you would have to consider, such as zeroes after a decimal point count except if they are preceded by all zeroes (3.00 has 3, 0.03 has 1). In this case, the regex regrettably becomes much more contrived, but I would use something like <code>"(^0+(\\.?)0*|(~\\.)0+$|\\.)"</code> to split on. See code below (Note -- still works on integers)</p> <pre><code>String myfloat = "0.0120"; String [] sig_figs = myfloat.split("(^0+(\\.?)0*|(~\\.)0+$|\\.)"); int sum = 0; for (String fig : sig_figs) { sum += fig.length(); } return sum; </code></pre> <p>Here's a quick look into the regex:</p> <p><code>^0+(\\.?)0*</code> means one or more leading zeroes (<code>0+</code>) followed optionally by a decimal (<code>\\.?</code>) and then zero or more zeroes (<code>0*</code>).</p> <p><code>(~\\.)0+$</code> means we want to take off ending zeroes (<code>0+$</code>), but only if they aren't preceded by a decimal (<code>(~\\.)</code>).</p> <p><code>\\.</code> means split whatever is left by the decimal point.</p>
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    1. CO@CB sorry I am responding so late but How is it that it is splitting the String exactly like that
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    2. CO@user3097544 updated the answer to breakdown the more complicated regex.
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