StackOverflow2013

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2013-12-22T19:05:07.300
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2013-12-22T19:07:42.563
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As of the latest iOS SDK, calling <code>[NSDate alloc]</code> always returns the same memory location. You can verify this behavior with the following code: <pre><code>NSDate *date1, *date2; date1 = [NSDate alloc]; NSLog(@"date1: %p", date1); date1 = [date1 init]; NSLog(@"date1: %p", date1); date2 = [NSDate alloc]; NSLog(@"date2: %p", date2); date2 = [date2 init]; NSLog(@"date2: %p", date2); </code></pre> I suspect that it has to do with the fact that <code>NSDate</code> is a <a href="https://developer.apple.com/library/ios/documentation/general/conceptual/CocoaEncyclopedia/ClassClusters/ClassClusters.html" rel="nofollow">class cluster</a>. If the private subclasses of a class cluster have different storage requirements, it's impossible to know inside of <code>alloc</code> how much memory to allocate. One approach to solving this problem, and it appears this is the approach that Apple is using with <code>NSDate</code>, is to let the <code>init</code> and factory methods handle all the memory allocation, since those methods know what private subclass is actually going to be used. At that point, all <code>alloc</code> is doing for you is allowing the user to preserve the <code>[[NSDate alloc] init]</code> pattern that's used for object creation everywhere in Objective-C. Since the memory location returned by <code>alloc</code> is always discarded, <code>alloc</code> may as well just return a fixed memory location, which is what it appears to be doing.
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1. This table or related slice is empty.
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1. POalloc + init memory usage mechanism
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1. USLorenzo B
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