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    <p>For reference, the following links seem related:</p> <ol> <li><a href="https://stackoverflow.com/questions/7319494/overloading-virtual-functions-of-the-same-name-from-different-base-classes-is-i?rq=1">Overloading virtual functions of the same name from different base classes. Is it possible?</a></li> <li><a href="https://stackoverflow.com/questions/3150310/c-virtual-override-functions-with-same-name">C++ virtual override functions with same name</a></li> <li><a href="https://stackoverflow.com/questions/14176916/derived-class-defines-function-via-base-class?rq=1">Derived class defines function via base class</a></li> </ol> <p>The OP in the second link asked if he could do something like you asked:</p> <pre><code>class Impl : public A , public B { public: void A::Function () { cout &lt;&lt; "A::Function" &lt;&lt; endl; } void B::Function () { cout &lt;&lt; "B::Function" &lt;&lt; endl; } }; </code></pre> <p>Johannes answer is:</p> <blockquote> <p>You cannot use qualified names there. I you write void Function() { ... } you are overriding both functions. Herb Sutter shows how it can be solved.</p> <p>Another option is to rename those functions, because apparently they do something different (otherwise i don't see the problem of overriding both with identical behavior).</p> </blockquote> <p>So one possible solution (by James Kanze from the first link) looks like this:</p> <pre><code>class RemapA : public A { virtual void fnInA() = 0; public: virtual void fn() { fnInA(); } }; class RemapB : public B { virtual int fnInB() = 0; public: virtual int fn() { return fnInB(); } }; class C : public RemapA, public RemapB { virtual void fnInA() { /* ... */ } virtual void fnInB() { /* ... */ } // ... }; </code></pre> <p>Herb Sutter's link essentially says the same thing.</p>
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