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    <p>html:</p> <pre><code>&lt;form&gt; &lt;input type="hidden" name="prod"&gt; &lt;div id="thumbs"&gt; &lt;!-- Dynamically created thumbnails start --&gt; &lt;img id="pic-1" src="url"&gt; &lt;img id="pic-2" src="url"&gt; &lt;img id="pic-3" src="url"&gt; &lt;!-- Dynamically created thumbnails end --&gt; &lt;/div&gt; &lt;/form&gt; </code></pre> <p>js:</p> <pre><code>$('#thumbs').delegate('img', 'click', function() { var $this = $(this); // Clear formatting $('#thumbs img').removeClass('border-highlight'); // Highlight with coloured border $this.addClass('border-highlight'); // Changes the value of the form field "prod" to the value of img.id $('[name="prod"]').val( $this.attr('id').substring($this.attr('id').lastIndexOf('-')+1) }); </code></pre> <p>fiddle <a href="http://jsfiddle.net/9rFKB/42/" rel="nofollow">link</a></p> <p>explanation: js/jquery catches the <code>click</code> on all <code>img</code> in <code>#thumbs</code> </p> <p>then removes all highlight effects and adds to the specific one, </p> <p>then it takes the image <code>$this</code> and gets it <code>id</code> value, it splits it at the <code>-</code> symbol and takes the scondpart (the value) and sets the value of <code>&lt;input type="hidden" name="prod"&gt;</code> to it.</p> <p>you dont have to change any php, since <code>&lt;input type="hidden" name="prod"&gt;</code> sends to <code>$_POST['prod']</code> the <code>name</code> attribute does the trick</p> <p>if you use the fiddle version, just remove the alert line... its just for debug reasons since js doesn't provide proper debug mechanisms</p>
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    1. COcould you make a fiddle and demonstrate please?
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    2. COAh, I see, but how do I forward the value of the `ID` to the variable `$prod` in `$prod = $_POST['prod'];` ?
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    3. COi updated the script and link...
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