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    <p>How were the records inserted? </p> <p>Date fields do store time information, and thus when inserting records using sysdate, the date field will contain different "values" for records within that day. When you execute date_proc = '05-JUL-08', you are saying where date_proc equals exactly the 5th of July 2008 at 12:01:00. If you inserted the record at 12:01 with sysdate, it will not be returned. Have you tried using a between or trunc?</p> <p>Here is an example:</p> <pre><code>drop table test_date; create table test_date (id number, ud date); insert into test_date values (1, '15-jan-10'); insert into test_date values (2, '15-jan-10'); insert into test_date values (3, '15-jan-10'); insert into test_date values (6, sysdate); -- sysdate as of writing is 15-JAN-2010 08:01:55 insert into test_date values (7, sysdate); -- sysdate as of writing is 15-JAN-2010 08:01:55 insert into test_date values (8, '16-jan-10'); commit; select id, ud, to_char(ud, 'dd-MON-yyyy HH:MM:SS') from test_date where ud = '15-jan-10'; ---------------------- ------------------------- -------------------- 1 15-JAN-10 15-JAN-2010 12:01:00 2 15-JAN-10 15-JAN-2010 12:01:00 3 15-JAN-10 15-JAN-2010 12:01:00 select id, ud, to_char(ud, 'dd-MON-yyyy HH:MM:SS') from test_date where trunc(ud) = '15-jan-2010'; ---------------------- ------------------------- -------------------- 1 15-JAN-10 15-JAN-2010 12:01:00 2 15-JAN-10 15-JAN-2010 12:01:00 3 15-JAN-10 15-JAN-2010 12:01:00 6 15-JAN-10 15-JAN-2010 08:01:55 7 15-JAN-10 15-JAN-2010 08:01:55 </code></pre>
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    1. POOracle OCI: Query with Date field
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    1. COHi RC, I tried trunc(). I added further info about how I inserted the record.
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