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    <p>I would turn it into a plugin and use it this way:</p> <pre><code>$.loadImages = function($images, callback) { var imgCount = $images.length; if (!imgCount) { callback(); } else { $images.each(function () { /*$(this).one("load error", function () { imgCount--; if (imgCount == 0) { callback(); } }); if (this.complete) $(this).load();*/ var img = new Image(); $(img).on("load error", function(){ imgCount--; if (imgCount == 0) { callback(); } }); img.src = this.src; }); } }; $.fn.loadImages = function (callback) { var $images = this.find("img").addBack().filter("img"); var self = this; $.loadImages($images,function(){ if ($.isFunction(callback)) { callback(); } self.trigger("imagesLoaded"); }); }; </code></pre> <p>Now you can use it like this:</p> <pre><code>$.loadImages($("div.image-container").find("img"), function() { console.log("Images loaded"); }); </code></pre> <p>or you can use it like this:</p> <pre><code>$("div.image-container").on("imagesLoaded",function(){ console.log("Images loaded"); }).loadImages(); </code></pre> <p>or even like this:</p> <pre><code>$("div.image-container").loadImages(function(){ console.log("Images loaded"); }); </code></pre> <p>this works too:</p> <pre><code>$("div.image-container img").loadImages(function(){ console.log("Images loaded"); }); </code></pre> <p>There is no way of making .on automatically cause the plugin to run without monkeypatching .on, which is usually a bad idea. It might look something like this:</p> <pre><code>var oldOn = $.fn.on $.fn.on = function() { var ret = oldOn.apply(this,arguments); if (arguments[0] == "imagesloaded") { var self = this; onImagesLoaded(this,function(){ self.trigger("imagesloaded"); }); } return ret; }; </code></pre>
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    1. COyou may also need to take into account the fact that the image might be loaded before the dom ready event is fired... so the `load error` event will not get triggered
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      1. USArun P Johny
    2. COI would solve that by creating new images and preloading that way, i just didn't want to rewrite everything he did
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      1. USKevin B
    3. COThanks Kevin. I think this is the route I'm going to end up going down, which is what I expected. I ideally wanted to find out that there is a way of using `on`, without "monkeypatching it" :p
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