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2013-12-18T16:57:10.837
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2014-10-21T15:26:31.810
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I've found <a href="https://github.com/astropy/astropy/blob/master/astropy/units/tests/test_units.py" rel="nofollow">astropy</a> to have a good units module. After some preparation you can do <pre><code>import astropy.units as u from functools import reduce u.Unit('MeV/fm').si #160.218 N eval('1*MeV/fm+3*N',u.__dict__).si #163.21765649999998 N from astropy.units import imperial u.__dict__.update(imperial.__dict__) u.sqmiles = u.mile**2 eval('3*cm/Ys**2 + 4e-4*sqmiles/km/h**2',u.__dict__).si #7.993790464000001e-08 m / s2 </code></pre> The following function adds <code>scipy</code> CODATA constants as quantities to <code>astropy</code> units <pre><code>def units_and_constants(): """ >>> u = units_and_constants() >>> u.hartree_joule_relationship <Quantity 4.35974434e-18 J> >>> eval('1*MeV/fm+3*N',u.__dict__).si <Quantity 163.21765649999998 N> """ import astropy.units as u from astropy.units import imperial u.__dict__.update(imperial.__dict__) from scipy.constants import physical_constants, value, unit import string def qntty(x): un = unit(x) va = value(x) if un: return va*eval(un.strip().replace(' ','*').replace('^','**'),u.__dict__) else: return va u.sr = u.radian**2 u.E_h = qntty('hartree-joule relationship') u.c = qntty('speed of light in vacuum') u.C_90 = (1+4.6e-8)*u.C codata = {} for n, t in physical_constants.items(): v = qntty(n) for x in string.punctuation+' ': n = n.replace(x,'_') codata[n] = v u.__dict__.update(codata) return u </code></pre> <a href="http://yt-project.org/" rel="nofollow">yt</a> also <a href="http://ytep.readthedocs.org/en/latest/YTEPs/YTEP-0011.html" rel="nofollow">tackles a problem similar to yours</a>. Have a look at the <a href="https://bitbucket.org/MatthewTurk/yt/src/f157266200b526c63adde4e67971c932a169c4bb/yt/utilities/tests/test_units.py?at=yt-3.0" rel="nofollow">Test file</a> to see how it is used.
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1. POHow to parse and simplify a string like '3cm/µs² + 4e-4 sqmiles/km/h**2' treating physical units correctly?
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1. USRoland Puntaier
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1. USRoland Puntaier
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