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    <p>You can of course do it. Not nice, not useful, but can be done by manipulating your pointer.</p> <p>To understand, look at the layout of your array of structures in memory, let's say your array start at address 0x0000 :</p> <pre><code>0x0000 : array[0].first - first part of mys.first 0x0004 : array[0].first - second part of mys.first 0x0008 : array[0].second 0x000c : array[0].str[0-3] - first four elements of your string 0x0010 : array[0].str[4-7] - next four elements 0x0014 : array[0].str[8-9] - last two elements and padding 0x0018 : array[1].first - second element ! </code></pre> <p>...</p> <p>So you can see that between the same field of two consecutive elements of the array you have the size of the structure.</p> <p>To iterate over the same field of several consecutive structures in memory you then just need to declare a pointer pointing to the element of the first structure and increase it by the size of your structure to access the same field of next element of the array.</p> <p>In your case, it would then look like : </p> <pre class="lang-c prettyprint-override"><code>int i; struct mys my_array[SIZE]; char* my_iterator = &amp;my_array[0].second; for(i=0; i&lt;SIZE; i++) { fprintf(stdout, "second-&gt;%lu\n", *(unsigned long*)my_iterator); my_iterator += sizeof(mys); } </code></pre> <p>But this really doesn't look good, you can improve it a bit, but still it's not good practice to play with pointers when it's not needed.</p> <pre class="lang-c prettyprint-override"><code>int i; struct mys my_array[SIZE]; strut mys* my_iterator = &amp;my_array[0].second; for(i=0; i&lt;SIZE; i++, my_iterator++) { fprintf(stdout, "second-&gt;%lu\n", *(unsigned long*)my_iterator); } </code></pre>
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