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POPointer of array of structure
 

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    <p>Ok, I've got this code :</p> <pre><code>#include &lt;stdio.h&gt; #include &lt;stdlib.h&gt; #define ARR_SIZE 5 struct mys { double first; unsigned long second; char str[10]; }; int main(int argc, char** argv) { size_t i = 0; struct mys thes[ARR_SIZE] = { {1.1, 1, "First"}, {2.2, 2, "Second"}, {3.3, 3, "Third"}, {4.4, 4, "Fourth"}, {5.5, 5, "Fifth"} };//load array of structures with values for (; i &lt; ARR_SIZE; ++i) fprintf(stdout, "second-&gt;%lu\n", thes[i].second);//loop through array thes and print element second return (EXIT_SUCCESS); } </code></pre> <p>Now, I want to get the address of the element called second of the zeroth element thes and then use that to loop through the array thes and print each second element.</p> <pre><code>#include &lt;stdio.h&gt; #include &lt;stdlib.h&gt; #define ARR_SIZE 5 struct mys { double first; unsigned long second; char str[10]; }; int main(int argc, char** argv) { size_t i = 0; unsigned long * ptr = NULL;//pointer to unsigned long struct mys thes[ARR_SIZE] = { {1.1, 1, "First"}, {2.2, 2, "Second"}, {3.3, 3, "Third"}, {4.4, 4, "Fourth"}, {5.5, 5, "Fifth"} }; //first loop for (; i &lt; ARR_SIZE; ++i) fprintf(stdout, "second-&gt;%lu\n", thes[i].second); ptr = &amp;thes[0].second;//get the address of the second element of the zero'th array structure and store it in ptr // Now I want to use the above pointer ptr to loop through the array thes and display the second element like I did above, but I can't manage to do that. //The output of this loop should be the same as the first loop return (EXIT_SUCCESS); } </code></pre> <p>So, I've implemented the pointer but I'm having problem writing the code for the second loop. Any help is appreciated.</p>
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    1. CO@itwasntpete my code is C :)
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