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POnumber that should be returned is the first or last in the array
 

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    <p>i have got test scenarios for certain cases in my jasmine.. but i am not able to get the test cases for this three scenarios... can you tell me how to do it...</p> <ul> <li>the number that should be returned is the first or last in the array undefined values in the array (or NaN, Infinity, …)\ numbers with identical absolute values (e.g. -0.01 and 0.01)</li> </ul> <p>providing my fiddle too</p> <p><a href="http://jsfiddle.net/YYg8U/15/" rel="nofollow">http://jsfiddle.net/YYg8U/15/</a></p> <pre><code>var myNumbersToSort = [-1, 2, -3, 4, 0.3,1,-0.001]; function getClosestToZero(set) { if(0 === set.length) return null; var closest = Math.abs(set[0]), result = 0; for(var i in set) { var next = Math.abs(set[i]); if(closest &gt; next) { result = i; closest = next; } } return closest; } document.getElementById('output').innerHTML = (getClosestToZero(myNumbersToSort)); </code></pre> <p>jasmine</p> <pre><code>describe( 'getClosestToZero', function () { it( 'finds a positive unique number near zero', function () { expect( getClosestToZero( [-1, 0.5, 0.01, 3, -0.2] ) ).toBe( 0.01 ); } ); it( 'finds a negative unique number near zero', function () { expect( getClosestToZero( [-1, 0.5, -0.01, 3, -0.2] ) ).toBe( -0.01 ); } ); // your method actually doesn't pass this test // think about what your method *should* do here and if needed, fix it it( 'finds one of multiple identical numbers near zero', function () { expect( getClosestToZero( [-1, 0.5, 0.01, 0.01, 3, -0.2] ) ).toBe( 0.01 ); } ); } ); </code></pre>
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    1. USuser3102494
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    1. COLooking at the code, I'd imagine that your test doesn't pass the second test but should pass the third. This is because you compare and return the absolute value of the value. So the second test will return 0.01 as opposed to -0.01
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      1. UScbayram
    2. CO@cbayram: thanks for your reply..can you edit my fiddle and how to pass second test http://jsfiddle.net/YYg8U/15/
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