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The first answer delivers opposite results, the second the wrong values for screenWidth < 320 and screenWidth > 1200. This one is hopefully correct and maybe a little more readable: <pre><code>var calculatePercentageWidth = function(screenWidth) { var MAX_SCREEN = {percentage: 65, width: 1200}; var MIN_SCREEN = {percentage: 98, width: 320}; if (screenWidth < MIN_SCREEN.width) { return MIN_SCREEN.percentage; } else if (screenWidth > MAX_SCREEN.width) { return MAX_SCREEN.percentage; } else { var coefficient = (MIN_SCREEN.percentage - MAX_SCREEN.percentage) / (MAX_SCREEN.width - MIN_SCREEN.width); return Math.round(MAX_SCREEN.percentage + (screenWidth - MIN_SCREEN.width) * coefficient); } } </code></pre> If the values for the maximum and minimum width or percentage change, you only need to change the values in the constants at the top of the function. To calculate the percentageWidth for screenWidth = 760, write: <pre><code>calculatePercentageWidth(760); </code></pre> <a href="http://jsfiddle.net/xBCLw/" rel="nofollow">jsfiddle</a> <h2>Corrected version:</h2> <pre><code>var calculatePercentageWidth = function(screenWidth) { var MAX_SCREEN = {percentage: 65, width: 1200}; var MIN_SCREEN = {percentage: 98, width: 320}; if (screenWidth < MIN_SCREEN.width) { return MIN_SCREEN.percentage; } else if (screenWidth > MAX_SCREEN.width) { return MAX_SCREEN.percentage; } else { var coefficient = (MIN_SCREEN.percentage - MAX_SCREEN.percentage) / (MAX_SCREEN.width - MIN_SCREEN.width); return Math.round(MIN_SCREEN.percentage - (screenWidth - MIN_SCREEN.width) * coefficient); } } </code></pre> <a href="http://jsfiddle.net/xBCLw/1/" rel="nofollow">jsfiddle</a>
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1. POJavascript calculating a formula
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1. USbladerunner
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1. USbladerunner
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1. COThanks. This one is the wrong way round. If the screenWidth = 1200 & need the percentage to be 65. If the screenWidth = 320 I need the percentage to be 98.
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2. COYou are right, I added a corrected version.
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