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POProlog: Compare 2 Lists and find out if at least one member of the first list exists in the other one
 

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  1. POProlog: Compare 2 Lists and find out if at least one member of the first list exists in the other one
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    <p>In the quest of learning more about prolog (and in the interest of solving my assignment), I have come across a situation where I need to compare 2 lists and find out if <strong>AT LEAST ONE</strong> element match ...<br> Here is an example what I want to do:</p> <pre><code>?-match([a,b,c],[x,y,z]). no. ?-match([a,b,c],[x,y,b]). yes. </code></pre> <p>My solution up to now: </p> <pre><code>compare_list([],[]). compare_list([],_). compare_list([L1Head|L1Tail],List2):- member(L1Head,List2), compare_list(L1Tail,List2). </code></pre> <p>but this solution gives a <code>true</code> when all the members of List1 are present in List2! </p> <p>Please people, don't think that I am cheating on an assignment, the problem is much much more complex, I am just stuck at this point and need help to get out of this sticky corner... otherwise I have done the entire assignment myself! </p>
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    1. USMarci-man
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      1. POProlog: Compare 2 Lists and find out if at least one member of the first list exists in the other one
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    1. CODoes your school allow you to ask for help on your assignments? most schools don't and consider it an academic offense.
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    2. CO@ChristianF this is not my main assignment... it is much more complex, I am just stuck on this small problem...
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      1. USMarci-man
    3. COThis is a fairly basic list processing problem. I'd suggest looking up some examples of list processing (such as here: http://www.ic.unicamp.br/~meidanis/courses/mc336/2009s2/prolog/problemas/) and have a look at the `member/2` predicate in the prolog documentation.
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      1. USlurker
 

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