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POWPF Popup Control - Find X, Y Coordinates
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2051934
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CreationDate
2010-01-12T20:01:19.760
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2017-05-08T19:42:27.607
LastEditDate
2010-01-13T14:58:02.850
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249196
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Score
6
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Body
I'm trying to get the X,Y coordinates of a popup control. I have tried: VisualTreeHelper.GetOffset(Popup); but the vector returned always contains (0,0) for X and Y. The parent of the popup is the layout root, which is a grid. The CustomPopupPlacementCallback also always returns 0,0 for it's Point parameter. The goal is to allow the user to drag the popup anywhere on the screen. I was going to try and accomplish this by getting the current popup and mouse position, and moving the popup in the same direction of the mouse moves. --------------------Update-------------------- Chris Nicol, I have tried your answer with the following code, but still receive 0,0 for rootPoint: Xaml: <pre><code><Window xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" x:Class="Test.MainWindow" x:Name="Window" Title="MainWindow" Width="800" Height="600"> <Grid x:Name="LayoutRoot"> <Popup x:Name="Popup" IsOpen="True" Placement="Center" Width="100" Height="100"> <Button Click="Button_Click" Content="Test" /> </Popup> </Grid> </code></pre> Code Behind: <pre><code>public partial class MainWindow : Window { public MainWindow() { this.InitializeComponent(); // Insert code required on object creation below this point. } private void Button_Click(object sender, RoutedEventArgs e) { GeneralTransform transform = Popup.TransformToAncestor(LayoutRoot); Point rootPoint = transform.Transform(new Point(0, 0)); } } </code></pre>
Tags
<c#><wpf><xaml><popup>
Title
WPF Popup Control - Find X, Y Coordinates
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