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    <p>The problem can be broken down to several steps:</p> <ol> <li>Populate a list with English words</li> <li>Split the sentence into terms delimited by white-space.</li> <li>Treat terms starting with '#' as hashtags</li> <li>For each hashtag, find words by longest match by checking if they exist in the list of words.</li> </ol> <p>Here is one solution using this approach:</p> <pre><code># Returns a list of common english terms (words) def initialize_words(): content = None with open('C:\wordlist.txt') as f: # A file containing common english words content = f.readlines() return [word.rstrip('\n') for word in content] def parse_sentence(sentence, wordlist): new_sentence = "" # output terms = sentence.split(' ') for term in terms: if term[0] == '#': # this is a hashtag, parse it new_sentence += parse_tag(term, wordlist) else: # Just append the word new_sentence += term new_sentence += " " return new_sentence def parse_tag(term, wordlist): words = [] # Remove hashtag, split by dash tags = term[1:].split('-') for tag in tags: word = find_word(tag, wordlist) while word != None and len(tag) &gt; 0: words.append(word) if len(tag) == len(word): # Special case for when eating rest of word break tag = tag[len(word):] word = find_word(tag, wordlist) return " ".join(words) def find_word(token, wordlist): i = len(token) + 1 while i &gt; 1: i -= 1 if token[:i] in wordlist: return token[:i] return None wordlist = initialize_words() sentence = "big #awesome-dayofmylife because #iamgreat" parse_sentence(sentence, wordlist) </code></pre> <p>It prints:</p> <pre><code>'big awe some day of my life because i am great ' </code></pre> <p>You will have to remove the trailing space, but that's easy. :)</p> <p>I got the wordlist from <a href="http://www-personal.umich.edu/~jlawler/wordlist" rel="nofollow noreferrer">http://www-personal.umich.edu/~jlawler/wordlist</a>.</p>
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    1. POTerm split by hashtag of multiple words
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    1. COHi, can you please explain your code?
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    2. COYes, will improve my answer in short.
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