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    <p>All the commentators above are correct of course: A hashtag without spaces or other clear separators between the words (especially in English) is often ambiguous and cannot be parsed correctly in all cases.</p> <p>However, the idea of the word list is rather simple to implement and might yield useful (albeit sometimes wrong) results nevertheless, so I implemented a quick version of that:</p> <pre><code>wordList = '''awesome day of my life because i am great something some thing things unclear sun clear'''.split() wordOr = '|'.join(wordList) def splitHashTag(hashTag): for wordSequence in re.findall('(?:' + wordOr + ')+', hashTag): print ':', wordSequence for word in re.findall(wordOr, wordSequence): print word, print for hashTag in '''awesome-dayofmylife iamgreat something somethingsunclear'''.split(): print '###', hashTag splitHashTag(hashTag) </code></pre> <p>This prints:</p> <pre><code>### awesome-dayofmylife : awesome awesome : dayofmylife day of my life ### iamgreat : iamgreat i am great ### something : something something ### somethingsunclear : somethingsunclear something sun clear </code></pre> <p>And as you see it falls into the trap qstebom has set for it ;-)</p> <p>EDIT:</p> <p>Some explanations of the code above:</p> <p>The variable <code>wordOr</code> contains a string of all words, separated by a pipe symbol (<code>|</code>). In regular expressions that means "one of these words".</p> <p>The first <code>findall</code> gets a pattern which means "a sequence of one or more of these words", so it matches things like "dayofmylife". The <code>findall</code> finds all these sequences, so I iterate over them (<code>for wordSequence in …</code>). For each word sequence then I search each single word (also using <code>findall</code>) in the sequence and print that word.</p>
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    1. POTerm split by hashtag of multiple words
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    1. COYes, something sun clear! ;(
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    2. CO@Alfe can you please explain your code? What is wordOr, wordSequence
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    3. COI added some explanation to my answer.
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