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    <p>Python the language does not define the order of the keys; any implementation can use any order it wants. <a href="http://docs.python.org/3/library/stdtypes.html#dictionary-view-objects" rel="nofollow">The documentation</a> says:</p> <blockquote> <p>Keys and values are iterated over in an arbitrary order which is non-random, varies across Python implementations, and depends on the dictionary’s history of insertions and deletions.</p> </blockquote> <p>(The wording and location in the docs are slightly different in 2.x, but the idea is the same.)</p> <p>If you're asking specifically about the CPython implementation, the details have changed twice between early 2.x and 3.4, so you'd have to ask about a specific version, not CPython in general. And they're pretty complicated details, as Max Noel's answer implies.</p> <p>But really:</p> <ul> <li>It should never matter for almost any code.</li> <li>If it does matter, you probably want to read the source for the implementation(s) you care about, because most of them don't document it. For example, in CPython, see <a href="http://hg.python.org/cpython/file/9f38bbd4e041/Objects/dictobject.c" rel="nofollow">dictobject.c</a> (for the version you need).</li> </ul> <p>The one thing you <em>can</em> count on is that if you iterate the same dictionary repeatedly without changing it, the order will be consistent.</p> <p>If you want something that acts like a dictionary but preserves the insertion order of the keys, see <a href="http://docs.python.org/3/library/collections.html#collections.OrderedDict" rel="nofollow"><code>collections.OrderedDict</code></a> in the standard library. If you something that acts like a dictionary but keeps the keys in sorted order, you probably want a tree-based structure; there are multiple third-party options to choose from, like <a href="https://pypi.python.org/pypi/blist/" rel="nofollow"><code>blist.sorteddict</code></a> and <a href="https://pypi.python.org/pypi/bintrees/" rel="nofollow"><code>bintrees.FastRBTree</code></a>.</p>
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