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    <p>First of all, yes there is a crazy regex you can give to String.split:</p> <pre><code>"[^A-Z0-9]+|(?&lt;=[A-Z])(?=[0-9])|(?&lt;=[0-9])(?=[A-Z])" </code></pre> <p>What this means is to split on any sequence of characters which aren't digits or capital letters as well as between any occurrence of a capital letter followed by a digit or any digit followed by a capital letter. The trick here is to match the space between a capital letter and a digit (or vice-versa) without consuming the letter or the digit. For this we use look-behind to match the part before the split and look-ahead to match the part after the split.</p> <p>However as you've probably noticed, the above regex is quite a bit more complicated than your VALID_PATTERN. This is because what you're really doing is trying to extract certain parts from the string, not to split it.</p> <p>So finding all the parts of the string which match the pattern and putting them in a list is the more natural approach to the problem. This is what your code does, but it does so in a needlessly complicated way. You can greatly simplify your code, by simply using Pattern.matcher like this:</p> <pre><code>private static final Pattern VALID_PATTERN = Pattern.compile("[0-9]+|[A-Z]+"); private List&lt;String&gt; parse(String toParse) { List&lt;String&gt; chunks = new LinkedList&lt;String&gt;(); Matcher matcher = VALID_PATTERN.matcher(toParse); while (matcher.find()) { chunks.add( matcher.group() ); } return chunks; } </code></pre> <p>If you do something like this more than once, you might want to refactor the body of this method into a method findAll which takes the string and the pattern as arguments, and then call it as findAll(toParse, VALID_PATTERN) in parse.</p>
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    1. POhow to seprate alphanumeric string into number and alphabets
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    1. USakshay
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    1. COIf it works for you, dont forget to mark it as accepted.
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