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POHow to use variable with LOAD DATA INFILE MYSQL, PHP
 

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  1. POHow to use variable with LOAD DATA INFILE MYSQL, PHP
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    <p>I have the following code, which correctly inserts data into the mysql database, however when I upload the file, that particular file will never contain a certain column called 'date' which exists in the mysql table. I would like to put it in with each row... So Basically, how do I make the last column the variable $dadate?</p> <p>Here is the code:</p> <pre><code>&lt;?php require_once('header2.php'); require_once('access.php'); ?&gt; &lt;head&gt; &lt;title&gt;Upload&lt;/title&gt; &lt;/head&gt; &lt;body&gt; &lt;?php $filedir = addslashes($_FILES['file']['tmp_name']); $dadate = $_POST['datadate']; echo $dadate; if (isset($_POST['submit'])) { $sql="LOAD DATA LOCAL INFILE '$filedir' INTO TABLE employeehourstest FIELDS TERMINATED BY ',' LINES TERMINATED BY '\r\n' IGNORE 18 LINES (@dummy, @dummy, @dummy, @dummy, employeeid, @dummy, @dummy, paycode, @dummy, @dummy, @dummy, employeehours, @dummy, @dummy, @dummy, @dummy, @dummy, @dummy, @dummy, @dummy)"; $result = mysql_query($sql); if (!$result) { die('Invalid query: ' . mysql_error()); } if ($result) { echo "&lt;h1&gt;" . "File ". $_FILES['file']['name'] ." uploaded successfully." . "&lt;/h1&gt;"; } } ?&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <p>Here is my table how it is uploaded with this code:</p> <p><img src="https://i.stack.imgur.com/1Hvi4.png" alt="enter image description here"></p> <p>Here is the php upload result with $dadate shown:</p> <p><img src="https://i.stack.imgur.com/gbpdk.png" alt="enter image description here"></p>
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    1. COwill you `echo` the `$_POST['datadate']` and post result it might be helpful to answer also show the text present in that file to help you
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    2. COdone! please see above, thanks
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    3. COwill you show the file content of that csv
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