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POajax and jquery select box post method using php and mysql
 

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  1. POajax and jquery select box post method using php and mysql
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    <p>I am using ajax and jquery select box post script.</p> <p>my problem is value id . When i clik the post then database table showing only id number. But i want to post is_kategorisi . What can i do ? <strong>This is my select box:</strong></p> <pre><code> &lt;?php include('db.php'); $is_kategorisi =$_POST['id']; $query = "SELECT * FROM business_category"; $res = mysql_query($query); ?&gt; &lt;select id="parent_category" name="sirket_kategorisi" accept-charset="UTF-8" /&gt; &lt;?php echo "&lt;option value=''&gt;Şirket Kategoriniz&lt;/option&gt;"; while($row = mysql_fetch_array($res)) { echo "&lt;option value='".$row['is_kategorisi']."'&gt;".ucfirst($row['is_kategorisi'])."&lt;/option&gt;"; } ?&gt; &lt;/select&gt; </code></pre> <p><strong>and this is my php code for post:</strong></p> <pre><code>&lt;?php include("includes/connect.php"); if(isset($_POST['submit'])){ $sirket_kategorisi = $_POST['sirket_kategorisi']; $query ="INSERT INTO `users` (`sirket_kategorisi`) VALUES ('$sirket_kategorisi')"; $result = mysql_query($query) or die(mysql_error()); if($result){ echo("&lt;center&gt;&lt;h1&gt;OK!&lt;/h1&gt;&lt;/center&gt;"); } else { echo("&lt;center&gt;&lt;h1&gt;Not OK!&lt;/h1&gt;&lt;/center&gt;"); } } ?&gt; </code></pre> <p><strong>ajax code :</strong></p> <pre><code>&lt;script type="text/javascript"&gt; $(document).ready(function() { $("#parent_category").change(function() { var category_id = $(this).val(); if(category_id != '') { $.ajax ({ type: "POST", url: "get_child.php", data: "category_id="+ category_id, success: function(option) { $("#child_category").html(option); } }); } else { $("#child_category").html("&lt;option value=''&gt;-- No category selected --&lt;/option&gt;"); } return false; }); }); &lt;/script&gt; </code></pre> <p><strong>get_child.php</strong></p> <pre><code>&lt;?php include('db.php'); ?&gt; &lt;?php if(isset($_POST['category_id']) &amp;&amp; $_POST['category_id'] != '') { $category_id = $_POST['category_id']; $category_id = mysql_real_escape_string($category_id); $query = "SELECT * FROM business_category_name where catg='".$category_id."'"; $res = mysql_query($query); if(mysql_num_rows($res)) { while($row = mysql_fetch_array($res)) { echo "&lt;option value='".$row['category_name']."'&gt;".ucfirst($row['category_name'])."&lt;/option&gt;"; } } } ?&gt; </code></pre>
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    1. PTQuestion
    1. USuser3072578
    1. USuser3072578
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    1. COplease print your data, and append in your question.
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      1. POajax and jquery select box post method using php and mysql
      1. USSuleman
    2. CO@Suleman this is table picture http://goo.gl/QOlnMA please check it
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      1. POajax and jquery select box post method using php and mysql
      1. USuser3072578
    3. COwhere is ajax and jQuery in this? also `Not OK!` part of the code will never be hit.
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      1. POajax and jquery select box post method using php and mysql
      1. USbansi
 

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