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20463790
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0
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0
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2013-12-09T05:30:11.070
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2013-12-10T02:27:17.710
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2017-05-23T12:08:06.007
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20369409
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2
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text
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<p>Here it is done with Recursion (Credit to this post's accepted answer:<a href="https://stackoverflow.com/questions/17934622/how-to-generate-permutations-with-repeated-characters?lq=1">How to Generate Permutations With Repeated Characters</a></p> <pre><code>program Combinations; {$APPTYPE CONSOLE} {$R *.res} uses System.SysUtils; procedure displayPermutation(const permutation : array of char; ilength: integer); var i: integer; begin for i := 0 to ilength - 1 do begin if i mod iLength = 0 then writeln('') else write(permutation[i]); end; end; procedure getPermutations(const operatorBank: array of char; operatorCount: integer; permutation: array of char; permutationLength, curIndex: integer); var i : integer; begin //stop recursion condition if(curIndex = permutationLength)then displayPermutation(permutation, permutationLength) else for i := 0 to operatorCount - 1 do begin permutation[curIndex] := operatorBank[i]; getPermutations(operatorBank,operatorCount,permutation, permutationLength,curIndex+1); end; end; var operatorBank,permutation : array of char; i, permutationLength, curIndex, operatorCount: integer; Q, S : String; begin try Q := ' '; S := ' '; while (Q <> '') and (S <> '') do begin Writeln(''); Write('P(N,R) N=? : '); ReadLn(Q); operatorCount := Length(Q); setLength(operatorBank,operatorCount); for i := 0 to operatorCount - 1 do operatorBank[i] := Q[i+1]; Write('P(N,R) R=? : '); ReadLn(S); if S <> '' then permutationLength := StrToInt(S) + 1; SetLength(permutation,operatorCount); curIndex := 0; Writeln(''); getPermutations(operatorBank, operatorCount, permutation, permutationLength, curIndex ); end; except on E: Exception do Writeln(E.ClassName, ': ', E.Message); end; end. </code></pre>
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1. POGenerate character combinations based on arbitrary string and length - similar to permutations
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1. PTAnswer
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1. USCommunity
UserOwnerUserId
1. USMerlin W.
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