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    <p>Basicly, you'll first make an array (RandomArray) filled with some random numbers between 1 and 5.</p> <pre><code>Random rnd = new Random(); int[] RandomArray = new int[5]; for (int i = 0; i &lt; 5; ++i) { RandomArray[i] = rnd.Next(1, 5); } </code></pre> <p>++i and i++ in this case will do the same.<br> Actually ++i means to first add 1 before taking the value and i++ means take the value of i and add one. But as I said, this doesn't make a difference in here</p> <p>Then you'll make a new array (Count) and you'll count those random numbers.<br> Because the random numbers are between 1 and 5, you'll need to subtract 1 from the number, otherwise you'll have OutOfBound Exceptions.</p> <pre><code>int[] Count = new int[5]; for (int i = 0; i &lt; 5; ++i) { Count[RandomArray[i]-1]++; } </code></pre> <p>After that, you'll print the results as a histogram, using a * for each counted number. Previously, you had to use i-1 to prevent OutOfBounds Exceptions. This means that the counts of the number 1 are stored under index 0, so add 1 add the end to display the correct result</p> <pre><code>for (int i = 0; i &lt; 5; ++i) { Console.Write("{0,2} Adet {1,2} &gt;&gt;&gt;&gt;", Count[i], i+1); for (int j = 0; j &lt; Count[i]; j++) { Console.Write("*"); } Console.WriteLine(); } </code></pre> <p><strong>Example</strong></p> <pre><code>RandomArray = [1, 3, 4, 1, 5]; Count = [2, 0, 1, 1, 1]; 2 Adet 1 &gt;&gt;&gt;&gt; ** 0 Adet 2 &gt;&gt;&gt;&gt; 1 Adet 3 &gt;&gt;&gt;&gt; * 1 Adet 4 &gt;&gt;&gt;&gt; * 1 Adet 5 &gt;&gt;&gt;&gt; * </code></pre>
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